版权声明:虽然写的很菜,但我也是有版权的! https://blog.csdn.net/weixin_42093825/article/details/82782611
简单例子:
#include <iostream>
#include <string>
using namespace std;
class Person
{
public:
Person(string nam, char s, int a)
{
name = nam;
sex = s;
age = a;
}
protected:
string name;
int age;
char sex;
};
class Teacher :virtual public Person
{
public:
Teacher(string nam, char s, int a, string t) :Person(nam, s, a)
{
title = t;
}
protected:
string title;
};
class Student :virtual public Person
{
public:
Student(string nam,char s,int a,float sco):Person(nam,s,a),score(sco){}
protected:
float score;
};
class Graduate :public Teacher, public Student
{
public:
Graduate(string nam,char s,int a,string t,float sco,float w)
:Person(nam,s,a),Teacher(nam,s,a,t),Student(nam,s,a,sco),wage(w){}
void show()
{
//这里之所以不存在二义性是因为这个菱形继承是虚基类继承,
//虚基类继承时c++只执行最后的派生类Grauate对虚基类的构造函数的调用,
//忽略虚基类的其他派生类的构造函数的调用,
//这保证了公共基类的数据成员不会被多次初始化。
cout << "name: " << name << endl;
cout << "age: " << age << endl;
cout << "sex; " << sex << endl;
cout << "score: " << score << endl;
cout << "title: " << title << endl;
cout << "wages: " << wage << endl;
}
private:
float wage;
};
// practice.cpp : 此文件包含 "main" 函数。程序执行将在此处开始并结束。
#include "pch.h"
#include "Person.h"
#include <iostream>
using namespace std;
int main()
{
Graduate grad("Wang_li", 'f', 24, "assistant", 89.5, 1200);
grad.show();
system("pause");
return 0;
}
这是一个菱形继承,Teacher和Student都继承于Person类,并且Person都是作为两者的虚基类,Graduate继承于Student和Teacher类,这时虚基类的优点就发挥出来了,Graduate负责对虚基类Person的初始化,忽略Student和Teacher对Person构造函数的调用,避免多次初始化。Graduate只保留了基类的成员,所以不会产生二义性并且解决菱形继承带来的数据冗余。如果只是普通继承,需要指明name这些成员的类域,不然编译器就不知道是哪个类的成员。
感谢我的朋友--小樊。
现在我的排名是1233662。