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思路一:通过Random.next获取随机下标
//1.数组里有{1,2,3,4,5,6,7,8,9,10},在一个
//新数组中进行随机打乱顺序。
public static int[] RandArray(int[] arr)
{
int[] newarr = new int[arr.Length];
int k = 0;
while (k < arr.Length)
{
int temp = new Random().Next(0, arr.Length);
if (arr[temp] != 0)
{
newarr[k] = arr[temp];
k++;
arr[temp] = 0;
}
}
for (int i = 0; i < arr.Length;i++)
{
Console.WriteLine(newarr[i]);
}
return newarr;
}
思路二:通过源数组进行操作
public static void RandArray01(int[] arr)
{
int[] newarr = new int[arr.Length];
int k = arr.Length;
for (int i = 0; i < arr.Length;i++)
{
int temp = new Random().Next(0, k);
newarr[i] = arr[temp];
//arr[temp]后面的数向前移一位
for (int j = temp; j < arr.Length-1;j++)
{
arr[j] = arr[j + 1];
}
k--;
}
for (int i = 0; i < arr.Length; i++)
{
Console.WriteLine(newarr[i]);
}
}