#思路判断不是列表或者元组的元素,直接输出
def outPutLetters(s):
for value in s:
if isinstance(value,(list,tuple)):
for v in value:
if isinstance(v,(list,tuple)):
for j in v:
print(j)
else:
print(v)
else:
print(value)
s= [[[1,2,3],4,5],7,8,(9,10,(11,12))]
print(outPutLetters(s))
2019-04-28:遍历一个列表中的嵌套列表和元组的所有元素, 将1-12的数字进行输出![[[1,2,3],4,5],7,8,(9,10,(11,12))]
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转载自blog.csdn.net/sinat_18722099/article/details/89645388
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