方法1:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* mergeTrees(TreeNode* t1, TreeNode* t2)
{
if(!t1 && !t2)
return nullptr;
if(!t1 && t2)
return t2;
if(t1 && !t2)
return t1;
DFS(t1, t2);
return t1;
}
void DFS(TreeNode *&t1, TreeNode *&t2)
{
if(t1 && t2)
t1->val += t2->val;
if(!t1 && t2)
{
t1 = t2;
return;
}
if(t1 && !t2)
return;
if(!t1 && !t2)
return;
DFS(t1->left, t2->left);
DFS(t1->right, t2->right);
}
};