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Question
Given a positive integer num, write a function which returns True if num is a perfect square else False.
Note: Do not use any built-in library function such as sqrt.
Example 1:
Input: 16
Returns: True
Example 2:
Input: 14
Returns: False
Algorithm
法1:二分查找
法2:牛顿迭代法
Code
二分查找:
class Solution {
public:
bool isPerfectSquare(int num) {
long long left=0,right=num/2+1;
while(left <= right){
long long mid = left+(right-left)/2;
if(mid*mid == num){
return true;
}
else if(mid*mid < num){
left = mid+1;
}
else{
right = mid-1;
}
}
return false;
}
};
牛顿迭代法:
class Solution {
public:
bool isPerfectSquare(int num) {
long r = num;
while (r*r > num)
r = (r + num/r) / 2;
return r*r == num;
}
};