MySQL刷题(Leecode)

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简单部分

1.编写一个 SQL 查询,获取 Employee 表中第二高的薪水(Salary)

 select (select distinct Salary from Employee order by Salary desc limit 1 offset 1) as SecondHighestSalary;

2.给定一个 Weather 表,编写一个 SQL 查询,来查找与之前(昨天的)日期相比温度更高的所有日期的 Id

select A.Id from Weather A 
inner join Weather B 
on A.Temperature > B.Temperature
and datediff(A.RecordDate,B.RecordDate)=1
SELECT w1.Id FROM Weather w1, Weather w2  
WHERE w1.Temperature > w2.Temperature AND TO_DAYS(w1.RecordDate)=TO_DAYS(w2.RecordDate) + 1; 

3.您需要编写一个 SQL查询,找出所有影片描述为非 boring (不无聊) 的并且 id 为奇数 的影片,结果请按等级 rating 排列

select * from cinema 
where description not like'boring'
and id&1
order by rating
  1. 给定 Employee 表,编写一个 SQL 查询,该查询可以获取收入超过他们经理的员工的姓名。
select A.Name from Employee A
inner join Employee B 
on A.ManagerId=B.Id
where A.Salary>B.Salary

5.编写一个 SQL 查询,查找 Person 表中所有重复的电子邮箱。

select distinct A.Email from Person A, Person B
where A.Email=B.Email and A.Id <> B.Id
select Email from Person group by Email having count(Email)>1

6.某网站包含两个表,Customers 表和 Orders 表。编写一个 SQL 查询,找出所有从不订购任何东西的客户。

select Name as Customers  
from Customers  
where Id not in(  
select C.Id  
from Customers as C, Orders as O  
where C.Id = O.CustomerId)  

7.编写一个 SQL 查询,满足条件:无论 person 是否有地址信息,都需要基于上述两表提供 person 的以下信息:

select Person.FirstName,Person. LastName, Address.City, Address.State from Person 
left join Address
on Person.PersonId=Address.PersonId

8.有一个courses 表 ,有: student (学生) 和 class (课程)。 请列出所有超过或等于5名学生的课

select class from courses 
group by class
having count(distinct student) >= 5

9.如果一个国家的面积超过300万平方公里,或者人口超过2500万,那么这个国家就是大国家。

select name,population,area from World 
where area>3000000 or population>25000000

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转载自blog.csdn.net/qq_40006058/article/details/80804065