题目
操作给定的二叉树,将其变换为源二叉树的镜像。
思路
先前序遍历这棵树的每个结点,如果遍历到的结点有子结点,就交换它的两个子节点,当交换完所有的非叶子结点的左右子结点之后,就得到了树的镜像。显然可以利用递归或者借助栈遍历二叉树来实现。
package com.zhumq.leetcode;
import java.util.ArrayDeque;
import java.util.Deque;
public class SymmetricTree {
/**
* 思路1:用栈遍历二叉树
*/
public void Mirror1(TreeNode root) {
if (root == null) {
return;
}
Deque<TreeNode> deque = new ArrayDeque<>();
deque.push(root);
while (!deque.isEmpty()) {
TreeNode node = deque.pop();
if (node.left != null || node.right != null) {
TreeNode temp = node.left;
node.left = node.right;
node.right = temp;
}
if (node.left != null) {
deque.push(node.left);
}
if (node.right != null) {
deque.push(node.right);
}
}
}
/**
* 思路2:递归
*/
public void Mirror2(TreeNode root) {
if (root == null) {
return;
}
if (root.left == null && root.right == null) {
return;
}
TreeNode temp = root.left;
root.left = root.right;
root.right = temp;
if (root.left != null) {
Mirror2(root.left);
}
if (root.right != null) {
Mirror2(root.right);
}
}
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
//递归使用数组创建树
public TreeNode createBinaryTreeByArray(int[] array, int index) {
TreeNode tn = null;
if (index < array.length) {
int value = array[index];
tn = new TreeNode(value);
tn.left = createBinaryTreeByArray(array, 2 * index + 1);
tn.right = createBinaryTreeByArray(array, 2 * index + 2);
return tn;
}
return tn;
}
public static void main(String[] args) {
SymmetricTree sy = new SymmetricTree();
int[] array = {8, 6, 10, 5, 7, 9, 11};
TreeNode treeNode = sy.createBinaryTreeByArray(array, 0);
System.out.println(treeNode.left.right.val);
sy.Mirror1(treeNode);
System.out.println(treeNode.left.right.val);
}
}