Mysql SQL查询今天、昨天、n天内、第n天

转载：https://blog.csdn.net/baidu_27222643/article/details/60467585

SQL语句如下：

注意：因为对索引列使用函数会导致索引失效，如果查询时需要使用到索引，请使用MySQL DATE_SUB() 函数

查询当天的所有数据

SELECT * FROM 表名 WHERE DATEDIFF(字段,NOW())=0

查询昨天的所有数据

SELECT * FROM 表名 WHERE DATEDIFF(字段,NOW())=-1

查询未来第n天的所有数据

//当n为负数时，表示过去第n天的数据
SELECT * FROM 表名WHERE DATEDIFF(字段,NOW())=n

查询未来n天内所有数据

//n天内
SELECT * FROM 表名 WHERE DATEDIFF(字段,NOW())<n AND DATEDIFF(字段,NOW())>=0

查询过去n天内所有数据

//包含当天
SELECT * FROM 表名 WHERE DATEDIFF(字段,NOW())<=0 AND DATEDIFF(字段,NOW())>-n
//不包含当天
SELECT * FROM 表名 WHERE DATEDIFF(字段,NOW())<0 AND DATEDIFF(字段,NOW())>-n

DATEDIFF函数说明：

DATEDIFF() 函数用于返回两个日期之间的天数。语法：DATEDIFF(date1,date2) date1 和 date2
参数是合法的日期或日期/时间表达式。注释：
1. 只有值的日期部分参与计算。
2. 当日期date1<date2时函数返回值为正数,date1=date2时函数返回值为0，date1>date2 时函数返回值为负数。
3. Mysql的DATEDIFF只有两个参数。SQL Server有三个参数，详细内容可见：SQL Date函数

转载于：https://blog.csdn.net/huangxy10/article/details/8193953

今天

select * from 表名 where to_days(时间字段名) = to_days(now());

昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

7天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

近30天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1

#查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查询上个月的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select *
from user
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select *
from [ user ]
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select *
from [ user ]
where pudate between 上月最后一天
and 下月第一天

where date(regdate) = curdate();

select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())

SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30

个人分类：数据库

Sun-k2016-10-27 17:09:57#3楼

楼主查昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1 这里用<= 今天的数据也会出来没有发现吗？推荐使用： SELECT * FROM 表明 WHERE date(DATE_FORMAT(时间字段名,'%Y-%m-%d')) = date_sub(curdate(),interval 1 day)

_林中人_2015-07-01 17:57:50#2楼

兄弟，TO_DAYS( )函数使用后还能用索引不？

yebai2014-07-10 07:27:43#1楼

有个问题吧： SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1 还应有个TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) > 0吧。