mysql 查询今天、昨天、上月、本月的数据

项目有用到过的sql

1、合并多行数据，逗号隔开（GROUP_CONCAT）

SELECT s.*,p.* from s_productandbrand s
 LEFT JOIN 
(SELECT ss.productID,GROUP_CONCAT(sp.`name`) as brandNames,GROUP_CONCAT(sp.itemID) as brandIds 


from s_pbref ss 
LEFT JOIN  s_productandbrand sp on ss.brandID =  sp.itemID 
GROUP BY ss.productID) p on s.itemID = p.productID
where 1 = 1

2、批量新增数据（insert select）

insert into s_msg(msgTypeID,userType,userID,orderID,createTime,visible,`desc`,state)
SELECT 1,1,1,0,NOW(),{2},'xx',1 
FROM u_users where type = 1 and `enable` = 1

批量新增数据2（）

insert into persons 

(id_p, lastname , firstName, city )

values

(200,'haha' , 'deng' , 'shenzhen'),

(201,'haha2' , 'deng' , 'GD'),

(202,'haha3' , 'deng' , 'Beijing');

3、批量更新数据

UPDATE s_configmoney a 
LEFT JOIN s_configmoney b on a.producterID = b.producterID and a.brandID = b.brandID and a.repairTypeID = b.repairTypeID and a.repairMaterial = b.repairMaterial
set a.designerMoney = b.designerMoney, a.designVerifyMoney = b.designVerifyMoney,a.producterMoney = b.producterMoney,a.state = b.state
where a.visible = 1 and a.producterID = {0} and b.visible=2

4、排序

ORDER BY if(oo.state=8,0,1),createtime desc

5、查询判断（select if）

SELECT if(job='boss','good','bad') as 'a' FROM `job`

'

6、left join 最新的表数据优化

LEFT JOIN (SELECT * FROM o_task WHERE taskID in (SELECT MAX(taskID) FROM o_task GROUP BY orderID )) ot on ot.orderID = o1.orderID 


LEFT JOIN (SELECT MAX(taskID) as taskID,orderID FROM o_task GROUP BY orderID ) ot1 on ot1.orderID = o1.orderID 
LEFT JOIN o_task ot on ot.taskID = ot1.taskID 

7:查询合并列数据GROUP_CONCAT

SELECT ss.productID,GROUP_CONCAT(sp.`name`) as brandNames,GROUP_CONCAT(sp.itemID) as brandIds ,GROUP_CONCAT(rt.`name`) as repairTypes
                                ,GROUP_CONCAT(rm.`name`) as repairMaterials,GROUP_CONCAT(rt.itemID) as repairTypeIds ,GROUP_CONCAT(rm.itemID) as repairMaterialIds 

                                from s_pbref ss 
                                LEFT JOIN  s_productandbrand sp on sp.visible = 1 and ss.brandID =  sp.itemID 
                                LEFT JOIN  s_repairmaterial rm on rm.visible = 1 and ss.repairMaterialID =  rm.itemID 
                                LEFT JOIN  s_repairtype rt on  rt.visible = 1 and ss.repairTypeID =  rt.itemID 


                      GROUP BY ss.productID
                            

7.1、按区域统计 （按12小时时间差统计）

select count(1) as count,(((diffHour - 1) div 12 + 1) * 12) as bttiem 
FROM (SELECT er.repairID,if(ec.receiverID >0,ec.receiverID,ec.userID) as repairUserID,convert(TIMESTAMPDIFF(HOUR,er.createTime,ec.createTime),SIGNED) as diffHour 
FROM eq_repair er 
LEFT JOIN eq_record ec on er.repairID = ec.repairID and ec.recordType = 20 
where ec.itemID >0  ORDER BY diffHour ) A 
where a.diffHour < 72
GROUP BY (a.diffHour -1) div 12 + 1

8：关于mysql查询最近一条记录

中策——查询排序后group by

select * from (
    select * from a
    where time<="2017-03-29 19:30:36" 
    order by time desc
)   group by user_id

后来发现使用group by 可以根据group by 的参数列分组，但返回的结果只有一条，仔细观察发现group by是将分组后的第一条记录返回。时间在查询后默认是顺序排列，因此需要先将时间倒序排列，方可取出距离当前最近一条。

这样查询实际上还是进行了两次查询，虽然时间上相比第一个方法有了质的飞跃，但是还可以进一步优化。

上策——将max() 方法和group by结合使用

select *,max(time) from a
where time<="2017-03-29 19:30:36" 
group by user_id

这句可以理解为将结果集根据user_id分组，每组取time最大一条记录。这样就很好的实现了批量查询最近记录，并且仅仅需要遍历一次表，即使在数据量巨大的情况下也可以在很短的时间查出结果。

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mysql 查询今天、昨天、上月、本月的数据

今天

select * from 表名 where to_days(时间字段名) = to_days(now());

昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1

7天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)

近30天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)

本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1

#查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));

查询当前这周的数据 
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());

查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;

查询当前月份的数据
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')

查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查询上个月的数据
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')

select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())

select * 
from user 
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select * 
from [ user ] 
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())

select * 
from [ user ] 
where pudate between 上月最后一天
and 下月第一天

where   date(regdate)   =   curdate();

select   *   from   test   where   year(regdate)=year(now())   and   month(regdate)=month(now())   and   day(regdate)=day(now())

SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30