6617:Finite Encyclopedia of Integer Sequences

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In Finite Encyclopedia of Integer Sequences (FEIS), all integer sequences of lengths between 1 and N (inclusive) consisting of integers between 1 and K (inclusive) are listed.
Let the total number of sequences listed in FEIS be X. Among those sequences, find the (X⁄2)-th (rounded up to the nearest integer) lexicographically smallest one.

Constraints
1≤N,K≤3×105
N and K are integers.

输入

Input is given from Standard Input in the following format:
K N

输出

Print the (X⁄2)-th (rounded up to the nearest integer) lexicographically smallest sequence listed in FEIS, with spaces in between, where X is the total number of sequences listed in FEIS.

样例输入

3 2

样例输出

2 1 

提示

There are 12 sequences listed in FEIS: (1),(1,1),(1,2),(1,3),(2),(2,1),(2,2),(2,3),(3),(3,1),(3,2),(3,3). The (12⁄2=6)-th lexicographically smallest one among them is (2,1).

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int a[300005];
int main()
{
	int k, n;
	scanf("%d%d", &k, &n);
	if(k % 2){
		for(int i = 1; i <= n; i++)
			a[i] = (k + 1) / 2;
		int t = n;
		for(int i = 1; i <= n / 2; i++){
			if(a[t] == 1){
				t--;
			}
			else{
				a[t]--;
				for(int j = t + 1; j <= n; j++)
					a[j] = k;
				t = n;
			}
		}
		for(int i = 1; i <= t; i++)
			if(i == t)
			printf("%d\n", a[i]);
			else
				printf("%d ", a[i]);
	}
	else{
		printf("%d", k / 2);
		for(int i = 0; i < n - 1; i++)
			printf(" %d", k);
		printf("\n");
	}
	return 0;
}