bugku-web-矛盾

版权声明：a3uRa QQ：962620891 github：asuralinmo.github.io https://blog.csdn.net/qq_41173457/article/details/82107924

$num=$_GET['num'];
if(!is_numeric($num))
{
echo $num;
if($num==1)
echo 'flag{**********}';
}

很简单，弱类型嘛，num=1xxxx就可以了