1 swagger-php根据自定义的规则生成API请求规则，通过phar生成json文件
2 打开swagger-ui/dist/index.html。输入json文件夹目录地址（需要同源），swagger-ui会根据请求的JSON生成API，页面很漂亮。输入请求参数后执行会获取返回值。
缺点：不能对返回的数据进行验证。功能类似chrome的插件postman。
Api Action测试参考代码：
Resource/PostAction.php
<?php
/**
* @SWG\Resource(
* apiVersion="2.2.0",
* swaggerVersion="1.2",
* basePath="http://test.xxx.com/Api/Post",
* resourcePath="/Post",
* description="Operations about Post",
* produces="['application/json']"
* )
*/
/**
* @SWG\Api(
* path="/apps",
* @SWG\Operation(
* method="POST",
* summary="Find app by buID",
* notes="Returns apps based on BUID",
* type="Post",
* nickname="apps",
* authorizations={},
* @SWG\Parameter(
* name="apiVersion",
* description="api version",
* required=true,
* type="integer",
* format="int64",
* paramType="form",
* minimum="1.0",
* allowMultiple=false
* ),
* @SWG\Parameter(
* name="sessionID",
* description="user login session",
* required=true,
* type="string",
* paramType="form",
* defaultValue="9f6cdd0858a1e93b1426659b283a93ec",
* allowMultiple=false
* ),
* @SWG\Parameter(
* name="buID",
* description="BU ID",
* required=true,
* type="int64",
* paramType="form",
* allowMultiple=false
* ),
* @SWG\ResponseMessage(code=400, message="Invalid ID supplied"),
* @SWG\ResponseMessage(code=404, message="Post not found"),
* @SWG\ResponseMessage(code=405, message="Invalid input"),
* @SWG\ResponseMessage(code=200, message="success")
* )
* )
*/
项目描述信息
Info/api.php
<?php /** * @SWG\Info( * title="MY Project", * description=" xxx", * ) * */
readme
# Usage of API Docs
### Raw Spec Structure
* Info - General Info.
* Model - Entity Class
* Resource - API endpoint
### Compile API info.
* after modify the spec, run shell script, as follows.
`cd api-docs`
`./genDocumentation.sh`
* the compiled content (.json) is stored in documentation/Output/
### View API docs
* visit http://{domain}/documenation/
sh 执行文件
#!/bin/sh ../swagger-php/swagger.phar ../output-docs -o ../documentation/output/