Java中如何合并有个具有相同key的Map

需求:查询两张表的数据,对数据进行合并。

/**
   * 查询全部.
   * 
   * @param entity
   * @param requestData
   * @return
   */
  @RequestMapping(value = "findAll", method = RequestMethod.GET)
  @ResponseBody
  public Map<String, Object> findAll(SysWorkflow entity, SysWorkflowPass pass, PageRequestData requestData) {
    Map<String, Object> map1 = workflowService.findAll(entity, requestData.getPageable());
    requestData.setPage(null);
    Map<String, Object> map2 = workflowPassService.findAll(pass, requestData.getPageable());
    return combine(map1, map2);
  }

private Map<String, Object> combine(Map<String, Object> map1, Map<String, Object> map2) {
    Map<String, Object> map = new HashMap<String, Object>();
    List<SysWorkflowPass> list2 = (List<SysWorkflowPass>) map2.get("data");
    List<SysWorkflow> list1 = (List<SysWorkflow>) map1.get("data");
    List<SysWorkFlowPassDto> list = new ArrayList<SysWorkFlowPassDto>();

    for (SysWorkflowPass sysWorkflowPass : list2) {
      SysWorkFlowPassDto dto = new SysWorkFlowPassDto();
      dto.setId(sysWorkflowPass.getId());
      dto.setCreateDate(sysWorkflowPass.getCreateDate());
      dto.setModifyDate(sysWorkflowPass.getModifyDate());
      dto.setSignedUsers(sysWorkflowPass.getSignedUsers());
      dto.setVersion(sysWorkflowPass.getVersion());
      dto.setWorkflowType(sysWorkflowPass.getWorkflowPass());
      dto.setName(sysWorkflowPass.getName());
      list.add(dto);
    }
    for (SysWorkflow sysWorkflow : list1) {
      SysWorkFlowPassDto dto = new SysWorkFlowPassDto();
      dto.setId(sysWorkflow.getId());
      dto.setCreateDate(sysWorkflow.getCreateDate());
      dto.setModifyDate(sysWorkflow.getModifyDate());
      dto.setSignedUsers(sysWorkflow.getSignedUsers());
      dto.setVersion(sysWorkflow.getVersion());
      dto.setWorkflowType(sysWorkflow.getWorkflowType().getName());
      dto.setName(sysWorkflow.getName());
      list.add(dto);
    }
    map.put("data", list);
    Long total1 = (Long) map1.get("total");
    Long total2 = (Long) map2.get("total");
    map.put("total", total1 + total2);
    map.put("success", "Boolean");
    return map;
  }

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转载自blog.csdn.net/xiao297328/article/details/82259754