Oracle数据库整理笔记
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2018-09-15 19:22:33
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create table employee
(
empno number(4) not null,
ename varchar2(10),
job varchar2(9),
mgr number(4),
hiredate date,
sal number(7,2),
comm number(7,2),
deptno number(2)
);
select * from employee;
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(1,'房钊','程序员',1,'2016-02-05',3000,2000,1);
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(2,'房钊','开发人员',3,'2017-06-05',5000,2000,2);
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(3,'房钊','测试人员',1,'2014-11-05',8000,5000,2);
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(4,'房钊','运维人员',2,'2017-02-02',10000,2300,1);
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(5,'房钊','发布',3,'2016-02-05',6300,36000,3);
insert into employee select * from scott.emp;
commit;
select * from employee;
create table bumen
(
buno number(2),
buname varchar2(50)
);
select * from bumen;
insert into bumen(buno,buname)
values(1,'开发部');
insert into bumen(buno,buname)
values(2,'测试部');
insert into bumen(buno,buname)
values(3,'设计部');
insert into bumen(buno,buname)
values(4,'运维部');
insert into bumen(buno,buname)
values(5,'管理部');
insert into bumen(buno,buname)
values(7902,'财务部');
insert into bumen(buno,buname)
values(7968,'福利部');
insert into bumen(buno,buname)
values(7698,'奖金部');
insert into bumen(buno,buname)
values(7839,'娱乐部');
insert into bumen(buno,buname)
values(7566,'搬砖部');
insert into bumen(buno,buname)
values(7788,'前台部');
insert into bumen(buno,buname)
values(7566,'看看部');
insert into bumen(buno,buname)
values(7782,'2222部');
insert into bumen(buno,buname)
values(7902,'1111部');
insert into bumen(buno,buname)
values(7839,'物流部');
insert into bumen(buno,buname)
values(7788,'废物部');
commit;
select * from bumen;
create table jinli
(
jno number(4),
jname varchar2(50)
);
commit;
select * from employee;
insert into jinli(jno,jname)values(1,'房钊');
insert into jinli(jno,jname)values(2,'房钊');
insert into jinli(jno,jname)values(3,'杜永杰');
insert into jinli(jno,jname)values(4,'王帅帅');
insert into jinli(jno,jname)values(5,'张思淼');
insert into jinli(jno,jname)values(7839,'李白');
insert into jinli(jno,jname)values(7499,'杜甫');
insert into jinli(jno,jname)values(7521,'王伟');
insert into jinli(jno,jname)values(7566,'王安石');
insert into jinli(jno,jname)values(7654,'冯巩');
insert into jinli(jno,jname)values(7698,'曾巩');
insert into jinli(jno,jname)values(7782,'欧阳修');
insert into jinli(jno,jname)values(7788,'王杰');
insert into jinli(jno,jname)values(7844,'马强');
insert into jinli(jno,jname)values(7876,'刘三单');
insert into jinli(jno,jname)values(7876,'李安');
insert into jinli(jno,jname)values(7900,'曹春喜');
insert into jinli(jno,jname)values(7902,'付婷婷');
insert into jinli(jno,jname)values(7934,'孙中天');
insert into jinli(jno,jname)values(7369,'李昂');
insert into jinli(jno,jname)values(7499,'金钟管');
insert into jinli(jno,jname)values(7521,'张瑞前');
insert into jinli(jno,jname)values(7566,'五保前');
insert into jinli(jno,jname)values(7654,'张何婷');
insert into jinli(jno,jname)values(7369,'孙浩');
select * from jinli;
delete from jinli where jno>5
delete from employee where rowid not in
(
select max(rowid) from employee group by empno
having (count(empno)>1)
union
select max(rowid) from employee group by empno
having (count(empno)=1)
);
delete from employee where empno >5;
select * from employee;
select * from bumen;
alter table employee
add constraint pk_empno primary key (empno);
alter table bumen
add constraint pk_buno primary key (buno);
alter table jinli
add constraint pk_jno primary key (jno);
alter table employee
add constraint fk_deptno foreign key(deptno) references bumen(buno);
alter table employee
add(empTel_no varchar2(12),
empAdress varchar2(20)
);
alter table employee
drop(empTel_no,empAdress);
select * from employee order by sal desc;
SELECT *
FROM (SELECT e.*,rownum rn FROM (SELECT * FROM employee ORDER BY sal DESC) e)
WHERE rn>=3 AND rn<=5;
select * from
(
select a.*,rownum rn from
(
select * from scott.emp
)
a
)
where rn between 3 and 5;
select * from
(
select a.*,rownum rn from
(
select * from scott.emp
)a
where rownum <=5
)
where rn >=3;
select * from (select a.*,rownum rn from (select * from employee order by sal desc) a) where
rn>=2 and rn<=5
select * from (
select employee.*,DENSE_RANK( ) over (partition by deptno order by sal desc) "DENSE_RANK"
from employee )e
where DENSE_RANK=2;
/*如何使用 Oracle Round 函数 (四舍五入)
描述 : 传回一个数值,该数值是按照指定的小数位元数进行四舍五入运算的结果。
SELECT ROUND(number, [ decimal_places ] ) FROM DUAL
参数:
number : 欲处理之数值
decimal_places : 四舍五入 , 小数取几位 ( 预设为 0 )
Sample :
select round(123.456, 0) from dual; 回传 123
select round(123.456, 1) from dual; 回传 123.5
select round(123.456, 2) from dual; 回传 123.46
select round(123.456, 3) from dual; 回传 123.456
select round(-123.456, 2) from dual; 回传 -123.46
*/
select ename "姓名",to_char(round (hiredate,'yyyy'),'YYYY')||'年度' 入职年度 from employee;
select distinct deptno from employee;
select * from employee where sal >(select sal from employee where ename='张三');
select ename,job,bumen.buname from employee,bumen where employee.deptno=bumen.buno and job='程序员';
select job, min(sal) from employee group by job having min(sal)>1500;
select * from employee where hiredate=last_day(hiredate);
/*
oracle的日期函数last_day 意思是得到每月的最后一天,用这个函数,我们可以得到各种不同的日期.
1:得到当前月第一天与最后一天
*/
select
to_char(trunc(sysdate,'MONTH'),'yyyymmdd')
firstday
, to_char(last_day(trunc(sysdate,'MONTH')),'yyyymmdd') lastday
from dual;
SELECT to_char( last_day(add_months(SYSDATE, -2)) + 1 ,'yyyymmdd') firstday
,to_char(last_day(add_months(SYSDATE, -1)),'yyyymmdd')
lastday
FROM dual;
SELECT
to_char( last_day(add_months(SYSDATE, -3)) + 1 ,'yyyymmdd')
firstday
,to_char(last_day(add_months(SYSDATE, -2)),'yyyymmdd')
lastday
FROM dual;
SELECT to_char( last_day(add_months(SYSDATE, 0)) + 1 ,'yyyymmdd')
firstday
,to_char(last_day(add_months(SYSDATE, 1)),'yyyymmdd')
lastday
FROM dual;
/*
======================================================
简答题p38
======================================================
*/
create table orders
(
order_id number(12) primary key,
order_date date not null,
order_mode varchar2(8) not null,
customer_id number(6) not null,
order_status number(2),
order_total number(8,2),
sales_rep_id number(6),
promotion_id number(6)
)
create table customers
(
customer_id number(6) not null,
cust_fiest_name varchar2(20) not null,
cust_last_name varchar2(20) not null,
nls_languages varchar2(3),
nls_territory varchar2(30),
credit_limit number(9,2),
cust_email varchar2(30),
account_mgr_id number(6),
marital_status varchar2(30),
gender char(1)
)
alter table customers modify (gender char(2));
alter table customers modify (nls_languages varchar2(10));
select * from customers
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('1','虎虎','王','汉语','山西吕梁','3000','[email protected]',1,'未婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('2','雄雄','穆','英语','山西吕梁','8000','[email protected]',2,'未婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('3','永杰','杜','俄语','中国北京','1568','[email protected]',1,'未婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('4','娇娇','宋','法语','山西太原','6000','[email protected]',3,'已婚','女');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('5','思淼','张','汉语','山东济南','6320','[email protected]',3,'未婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('6','春熙','曹','法语','山东济南','3600','[email protected]',2,'已婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('6','儿子','王','法语','AMERICA','56000','[email protected]',3,'已婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('8','孙子','Fssdfs','韩语','中国北京','6320','[email protected]',4,'未婚','女');
select * from customers
select * from orders;
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(1,'2017-02-09','网上下单',2,1,323.23,1,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(2,'2016-11-09','上门购买',1,2,56.00,2,1);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(3,'2017-12-20','熟人推荐',3,1,6000,1,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(4,'2015-12-02','网上下单',5,2,365,2,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(5,'2017-12-09','上门购买',3,1,3210,1,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(6,'2014-11-11','网上下单',3,1,630,2,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(7,'2017-01-01','上门购买',2,1,6300,1,2);
commit;
select * from orders;
select distinct nls_territory from customers;
select order_id 订单编号,b.cust_fiest_name 顾客姓氏,c.ename 经理名字 from orders a join customers b on a.customer_id=b.customer_id join employee c on b.account_mgr_id=c.empno
where order_id in
(
select order_id from orders where order_total>=1000 and order_total<=6000
);
select c.ename,c.sal from customers a join employee c on a.account_mgr_id=c.empno
where nls_territory='AMERICA'
select customer_id,nls_languages from Customers
where nls_territory='AMERICA' or nls_territory='山东济南' or nls_territory='中国北京';
select customer_id 客户编号,cust_email 邮箱 from customers
where cust_last_name like 'F%';
select cust_last_name,cust_fiest_name,b.order_id from customers a
join orders b on a.customer_id =b.customer_id
where a.customer_id in
(
select customer_id from orders
);
/*
2. 根据员工表(Employee表)编写一个语句,只有当最低工资少于 5000 而且最高工资超过7000时,才显示部门 ID 以及该部门支付的最低工资和最高工资。
*/
select deptno 部门编号,max(sal) 最高工资,min(sal) 最低工资 from employee
group by deptno
having min(sal)<5000 and max(sal)>7000;
/*
3. 根据员工表(Employee表)编写一个语句,显示各部门的每个工作类别中支付的最高工资
*/
select deptno,job,max(sal) from employee
group by deptno,job
order by deptno,job;
select to_char(sysdate,'YYYY"年"fmMM"月"fmDD"日" HH24:MI:SS') from dual;
select to_char(sysdate,'YYYY"年"MM"月"DD"日" HH24:MI:SS') from dual;
select * from dual;
select SYS_CONTEXT('USERENV','TERMINAL') from dual;
select TO_DATE ('2013-1-1','yyyy-mm-dd') from dual;
select to_date('21210213','yyyy-mm-dd') from dual;
select max(rowid) from student
group by sage,sname
having (count(sage||sname)>1);
union
select max(rowid) from student
group by sname,sage
having (count(sage||sname)=1);
/*
创建自增长
*/
create table grade
(
id number(2) not null primary key,
name varchar2(12)
)
create sequence grade_add
start with 1
increment by 1
nocycle
create or replace trigger grade_c
before insert on grade for each row when (new.id is null)
begin
select grade_add.nextval into:new.id from dual;
end;
insert into grade(name) values('12班');
insert into grade (name) values('13班');
insert into grade (name) values('14班');
insert into grade(name) values('15班');
insert into grade (name) values('16班');
insert into grade (name) values('17班');
select * from grade;
create table employee
(
empno number(4) not null,
ename varchar2(10),
job varchar2(9),
mgr number(4),
hiredate date,
sal number(7,2),
comm number(7,2),
deptno number(2)
);
select * from employee;
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(1,'张一','程序员',1,'2016-02-05',3000,2000,1);
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(2,'张二','开发人员',3,'2017-06-05',5000,2000,2);
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(3,'张三','测试人员',1,'2014-11-05',8000,5000,2);
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(4,'张四','运维人员',2,'2017-02-02',10000,2300,1);
insert into employee(empno,ename,job,mgr,hiredate,sal,comm,deptno)
values(5,'张五','发布',3,'2016-02-05',6300,36000,3);
insert into employee select * from scott.emp;
commit;
select * from employee;
create table bumen
(
buno number(2),
buname varchar2(50)
);
select * from bumen;
insert into bumen(buno,buname)
values(1,'开发部');
insert into bumen(buno,buname)
values(2,'测试部');
insert into bumen(buno,buname)
values(3,'设计部');
insert into bumen(buno,buname)
values(4,'运维部');
insert into bumen(buno,buname)
values(5,'管理部');
insert into bumen(buno,buname)
values(7902,'财务部');
insert into bumen(buno,buname)
values(7968,'福利部');
insert into bumen(buno,buname)
values(7698,'奖金部');
insert into bumen(buno,buname)
values(7839,'娱乐部');
insert into bumen(buno,buname)
values(7566,'搬砖部');
insert into bumen(buno,buname)
values(7788,'前台部');
insert into bumen(buno,buname)
values(7566,'看看部');
insert into bumen(buno,buname)
values(7782,'2222部');
insert into bumen(buno,buname)
values(7902,'1111部');
insert into bumen(buno,buname)
values(7839,'物流部');
insert into bumen(buno,buname)
values(7788,'废物部');
commit;
select * from bumen;
create table jinli
(
jno number(4),
jname varchar2(50)
);
commit;
select * from employee;
insert into jinli(jno,jname)values(1,'穆雄雄');
insert into jinli(jno,jname)values(2,'成志龙');
insert into jinli(jno,jname)values(3,'杜永杰');
insert into jinli(jno,jname)values(4,'王帅帅');
insert into jinli(jno,jname)values(5,'张思淼');
insert into jinli(jno,jname)values(7839,'李白');
insert into jinli(jno,jname)values(7499,'杜甫');
insert into jinli(jno,jname)values(7521,'王伟');
insert into jinli(jno,jname)values(7566,'王安石');
insert into jinli(jno,jname)values(7654,'冯巩');
insert into jinli(jno,jname)values(7698,'曾巩');
insert into jinli(jno,jname)values(7782,'欧阳修');
insert into jinli(jno,jname)values(7788,'王杰');
insert into jinli(jno,jname)values(7844,'马强');
insert into jinli(jno,jname)values(7876,'刘三单');
insert into jinli(jno,jname)values(7876,'李安');
insert into jinli(jno,jname)values(7900,'曹春喜');
insert into jinli(jno,jname)values(7902,'付婷婷');
insert into jinli(jno,jname)values(7934,'孙中天');
insert into jinli(jno,jname)values(7369,'李昂');
insert into jinli(jno,jname)values(7499,'金钟管');
insert into jinli(jno,jname)values(7521,'张瑞前');
insert into jinli(jno,jname)values(7566,'五保前');
insert into jinli(jno,jname)values(7654,'张何婷');
insert into jinli(jno,jname)values(7369,'孙浩');
select * from jinli;
delete from jinli where jno>5
delete from employee where rowid not in
(
select max(rowid) from employee group by empno
having (count(empno)>1)
union
select max(rowid) from employee group by empno
having (count(empno)=1)
);
delete from employee where empno >5;
select * from employee;
select * from bumen;
alter table employee
add constraint pk_empno primary key (empno);
alter table bumen
add constraint pk_buno primary key (buno);
alter table jinli
add constraint pk_jno primary key (jno);
alter table employee
add constraint fk_deptno foreign key(deptno) references bumen(buno);
alter table employee
add(empTel_no varchar2(12),
empAdress varchar2(20)
);
alter table employee
drop(empTel_no,empAdress);
select * from employee order by sal desc;
SELECT *
FROM (SELECT e.*,rownum rn FROM (SELECT * FROM employee ORDER BY sal DESC) e)
WHERE rn>=3 AND rn<=5;
select * from
(
select a.*,rownum rn from
(
select * from scott.emp
)
a
)
where rn between 3 and 5;
select * from
(
select a.*,rownum rn from
(
select * from scott.emp
)a
where rownum <=5
)
where rn >=3;
select * from (select a.*,rownum rn from (select * from employee order by sal desc) a) where
rn>=2 and rn<=5
select * from (
select employee.*,DENSE_RANK( ) over (partition by deptno order by sal desc) "DENSE_RANK"
from employee )e
where DENSE_RANK=2;
/*如何使用 Oracle Round 函数 (四舍五入)
描述 : 传回一个数值,该数值是按照指定的小数位元数进行四舍五入运算的结果。
SELECT ROUND(number, [ decimal_places ] ) FROM DUAL
参数:
number : 欲处理之数值
decimal_places : 四舍五入 , 小数取几位 ( 预设为 0 )
Sample :
select round(123.456, 0) from dual; 回传 123
select round(123.456, 1) from dual; 回传 123.5
select round(123.456, 2) from dual; 回传 123.46
select round(123.456, 3) from dual; 回传 123.456
select round(-123.456, 2) from dual; 回传 -123.46
*/
select ename "姓名",to_char(round (hiredate,'yyyy'),'YYYY')||'年度' 入职年度 from employee;
select distinct deptno from employee;
select * from employee where sal >(select sal from employee where ename='张三');
select ename,job,bumen.buname from employee,bumen where employee.deptno=bumen.buno and job='程序员';
select job, min(sal) from employee group by job having min(sal)>1500;
select * from employee where hiredate=last_day(hiredate);
/*
oracle的日期函数last_day 意思是得到每月的最后一天,用这个函数,我们可以得到各种不同的日期.
1:得到当前月第一天与最后一天
*/
select
to_char(trunc(sysdate,'MONTH'),'yyyymmdd')
firstday
, to_char(last_day(trunc(sysdate,'MONTH')),'yyyymmdd') lastday
from dual;
SELECT to_char( last_day(add_months(SYSDATE, -2)) + 1 ,'yyyymmdd') firstday
,to_char(last_day(add_months(SYSDATE, -1)),'yyyymmdd')
lastday
FROM dual;
SELECT
to_char( last_day(add_months(SYSDATE, -3)) + 1 ,'yyyymmdd')
firstday
,to_char(last_day(add_months(SYSDATE, -2)),'yyyymmdd')
lastday
FROM dual;
SELECT to_char( last_day(add_months(SYSDATE, 0)) + 1 ,'yyyymmdd')
firstday
,to_char(last_day(add_months(SYSDATE, 1)),'yyyymmdd')
lastday
FROM dual;
/*
======================================================
简答题p38
======================================================
*/
create table orders
(
order_id number(12) primary key,
order_date date not null,
order_mode varchar2(8) not null,
customer_id number(6) not null,
order_status number(2),
order_total number(8,2),
sales_rep_id number(6),
promotion_id number(6)
)
create table customers
(
customer_id number(6) not null,
cust_fiest_name varchar2(20) not null,
cust_last_name varchar2(20) not null,
nls_languages varchar2(3),
nls_territory varchar2(30),
credit_limit number(9,2),
cust_email varchar2(30),
account_mgr_id number(6),
marital_status varchar2(30),
gender char(1)
)
alter table customers modify (gender char(2));
alter table customers modify (nls_languages varchar2(10));
select * from customers
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('1','虎虎','王','汉语','山西吕梁','3000','[email protected]',1,'未婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('2','雄雄','穆','英语','山西吕梁','8000','[email protected]',2,'未婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('3','永杰','杜','俄语','中国北京','1568','[email protected]',1,'未婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('4','娇娇','宋','法语','山西太原','6000','[email protected]',3,'已婚','女');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('5','思淼','张','汉语','山东济南','6320','[email protected]',3,'未婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('6','春熙','曹','法语','山东济南','3600','[email protected]',2,'已婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('6','儿子','王','法语','AMERICA','56000','[email protected]',3,'已婚','男');
insert into customers (customer_id,cust_fiest_name,cust_last_name,nls_languages,nls_territory,credit_limit,cust_email,account_mgr_id,marital_status,gender)values('8','孙子','Fssdfs','韩语','中国北京','6320','[email protected]',4,'未婚','女');
select * from customers
select * from orders;
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(1,'2017-02-09','网上下单',2,1,323.23,1,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(2,'2016-11-09','上门购买',1,2,56.00,2,1);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(3,'2017-12-20','熟人推荐',3,1,6000,1,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(4,'2015-12-02','网上下单',5,2,365,2,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(5,'2017-12-09','上门购买',3,1,3210,1,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(6,'2014-11-11','网上下单',3,1,630,2,2);
insert into orders(order_id,order_date,order_mode,customer_id,order_status,order_total,sales_rep_id,promotion_id)
values(7,'2017-01-01','上门购买',2,1,6300,1,2);
commit;
select * from orders;
select distinct nls_territory from customers;
select order_id 订单编号,b.cust_fiest_name 顾客姓氏,c.ename 经理名字 from orders a join customers b on a.customer_id=b.customer_id join employee c on b.account_mgr_id=c.empno
where order_id in
(
select order_id from orders where order_total>=1000 and order_total<=6000
);
select c.ename,c.sal from customers a join employee c on a.account_mgr_id=c.empno
where nls_territory='AMERICA'
select customer_id,nls_languages from Customers
where nls_territory='AMERICA' or nls_territory='山东济南' or nls_territory='中国北京';
select customer_id 客户编号,cust_email 邮箱 from customers
where cust_last_name like 'F%';
select cust_last_name,cust_fiest_name,b.order_id from customers a
join orders b on a.customer_id =b.customer_id
where a.customer_id in
(
select customer_id from orders
);
/*
2. 根据员工表(Employee表)编写一个语句,只有当最低工资少于 5000 而且最高工资超过7000时,才显示部门 ID 以及该部门支付的最低工资和最高工资。
*/
select deptno 部门编号,max(sal) 最高工资,min(sal) 最低工资 from employee
group by deptno
having min(sal)<5000 and max(sal)>7000;
/*
3. 根据员工表(Employee表)编写一个语句,显示各部门的每个工作类别中支付的最高工资
*/
select deptno,job,max(sal) from employee
group by deptno,job
order by deptno,job;
select to_char(sysdate,'YYYY"年"fmMM"月"fmDD"日" HH24:MI:SS') from dual;
select to_char(sysdate,'YYYY"年"MM"月"DD"日" HH24:MI:SS') from dual;
select * from dual;
select SYS_CONTEXT('USERENV','TERMINAL') from dual;
select TO_DATE ('2013-1-1','yyyy-mm-dd') from dual;
select to_date('21210213','yyyy-mm-dd') from dual;
select max(rowid) from student
group by sage,sname
having (count(sage||sname)>1);
union
select max(rowid) from student
group by sname,sage
having (count(sage||sname)=1);
/*
创建自增长
*/
create table grade
(
id number(2) not null primary key,
name varchar2(12)
)
create sequence grade_add
start with 1
increment by 1
nocycle
create or replace trigger grade_c
before insert on grade for each row when (new.id is null)
begin
select grade_add.nextval into:new.id from dual;
end;
insert into grade(name) values('12班');
insert into grade (name) values('13班');
insert into grade (name) values('14班');
insert into grade(name) values('15班');
insert into grade (name) values('16班');
insert into grade (name) values('17班');
select * from grade;
转载自blog.csdn.net/fz121800/article/details/78734089