【CCF 201409-3】字符串匹配

版权声明: https://blog.csdn.net/leelitian3/article/details/82705643

字符串模拟水题,只要合理的运用STL的函数即可

#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;

int main()
{
	bool flag;
	int n;
	string a,b,alower,blower;
	cin>>a>>flag>>n;
	alower = a;
	transform(a.begin(),a.end(),alower.begin(),::tolower);
	
	while(n--)
	{
		cin>>b;
		blower = b;
		if(flag == 0)
		{
			transform(b.begin(),b.end(),blower.begin(),::tolower);
			if(blower.find(alower) != string::npos) cout<<b<<endl; 
		}
		else if(b.find(a) != string::npos) cout<<b<<endl;
	}
	
    return 0;
}

猜你喜欢

转载自blog.csdn.net/leelitian3/article/details/82705643