java:面向对象练习①-矩形案列练习

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public class Demo07_Test01 {
    public static void main(String[]args){
        Rectangle R1=new Rectangle();
        R1.setHigh(10);
        R1.setWidth(20);
        R1.getArea();
        System.out.println("矩形的面积是:"+R1.getArea());
        R1.getLength();
        System.out.println("矩形的周长是:"+R1.getLength());
        System.out.println("============================");
        Rectangle R2=new Rectangle(20,30);
        R2.getArea();
        System.out.println("矩形的面积是:"+R2.getArea());
        R2.getLength();
        System.out.println("矩形的周长是:"+R2.getLength());
    }
}

class Rectangle{
    private int high;//高
    private int width;//宽
    public Rectangle(){//无参构造函数

    }
    public Rectangle(int high,int width){//有参构造函数
        this.high=high;
        this.width=width;
    }

    public void setHigh(int high) {//设置高
        this.high = high;
    }

    public int getHigh() {//获取高
        return this.high;
    }

    public void setWidth(int width) {//设置宽
        this.width = width;
    }

    public int getWidth() {//获取宽
        return this.width;
    }

    public int getLength(){//矩形周长方法
        return 2*(this.width+this.high);
    }

    public int getArea(){//矩形面积方法
        return this.width*this.high;
    }
}

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转载自blog.csdn.net/qq_24644517/article/details/82292058
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