005. Python找到符合要求的子串

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Between markers

一、问题描述

要求:给定一个字符串以及两个标记(开始和结束标记),要求找到字符串中两个标记之间的子串。

注意

  • 开始和结束标记不同
  • 如果没有开始标记,默认从字符串第一个字符开始
  • 如果没有结束标记,默认字符串最后一位为结束
  • 如果开始和结束标记都没有,则返回整个字符串
  • 如果结束标记在开始标记之前,返回空字符串

输入:字符串、开始标记和结束标记

输出:字符串

示例

between_markers('What is >apple<', '>', '<') == 'apple'
between_markers('No[/b] hi', '[b]', '[/b]') == 'No'

二、解题示例

1. 简单直观

def between_markers(text: str, begin: str, end: str) -> str:
    """
        returns substring between two given markers
    """
    # your code here
    start_index = 0 if text.find(begin) == -1 else text.find(begin)
    len_begin = 0 if text.find(begin) == -1 else len(begin)

    end_index = text.find(end)

    if end_index == -1:
        return text[start_index++ len_begin:]
    else:
        return text[start_index + len_begin:end_index]


if __name__ == '__main__':
    print('Example:')
    print(between_markers('What is >apple<', '>', '<'))

    # These "asserts" are used for self-checking and not for testing
    assert between_markers('What is >apple<', '>', '<') == "apple", "One sym"
    assert between_markers("<head><title>My new site</title></head>",
                           "<title>", "</title>") == "My new site", "HTML"
    assert between_markers('No[/b] hi', '[b]', '[/b]') == 'No', 'No opened'
    print(between_markers('No [b]hi', '[b]', '[/b]'))
    assert between_markers('No [b]hi', '[b]', '[/b]') == 'hi', 'No close'
    assert between_markers('No hi', '[b]', '[/b]') == 'No hi', 'No markers at all'
    assert between_markers('No <hi>', '>', '<') == '', 'Wrong direction'
    print('Wow, you are doing pretty good. Time to check it!')

2

def between_markers(text: str, begin: str, end: str) -> str:
    start = text.find(begin) + len(begin) if begin in text else None
    stop = text.find(end) if end in text else None
    return text[start:stop]

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转载自blog.csdn.net/u014303046/article/details/82526230