1. 用map来处理字符串列表,把列表中的所有人都变成sb,比如alex_sb
name=['alex','wupeiqi','yuanhao','nezha']
name=['alex','wupeiqi','yuanhao','nezha'] generator=map(lambda x:x+'sb',name) #map函数返回的是一个generator print(list(generator)) #使用强制类型转换可以打印其中的值
运行结果:
2.用filter函数处理数字列表,将列表中的所有偶数筛选出来
generator=filter(lambda x:x%2==0,[1,3,5,6,7,8]) #filter函数返回一个迭代器 generator for i in generator: print(i)
运行结果:
3.随意写一个20行以上的文件,运行程序,先将内容读到内存中,使用列表存储,接收用户输入页码,每页5条。仅输出当页的内容
def func(): content=[] with open('info',mode='r',encoding='utf-8') as file: for line in file: content.append(line.strip()) return content def get_msg(): msg=int(input('please input the number of page(1-4):')) content=func() view_content=content[(msg-1)*5:msg*5] for i in view_content: print(i) get_msg()
运行结果:
4.如下,每个小字典的name对应股票名字,shares对应多少股,prices对应股票的价格:
portfolio=[ {'name':'IBM','shares':100,'price':91.1}, {'name':'AAPL','shares':50,'price':543.22}, {'name':'FB','shares':200,'price':21.09}, {'name':'HPQ','shares':35,'price':31.75}, {'name':'YHOO','shares':45,'price':16.35}, {'name':'ACME','shares':75,'price':115.65}, ]
4.1 计算购买每只股票的总价;
4.2 用filter过滤出,单价大于100的股票有哪些
portfolio=[ {'name':'IBM','shares':100,'price':91.1}, {'name':'AAPL','shares':50,'price':543.22}, {'name':'FB','shares':200,'price':21.09}, {'name':'HPQ','shares':35,'price':31.75}, {'name':'YHOO','shares':45,'price':16.35}, {'name':'ACME','shares':75,'price':115.65}, ] def func1(): price_total=0 for i in portfolio: price_total+=i['price'] return price_total price_total=func1() print(price_total) def func2(): generator=filter(lambda dict:dict['price']>100,portfolio) for i in generator: print(i['name']) func2()
第一问,出题的语文水平一定不高,微笑.jpg
所以我的理解就是每种股票都买一股,然后这六种股票的总价~