Leetcode 189. Rotate Array

Given an array, rotate the array to the right by k steps, where k is non-negative.

Example 1:

Input: [1,2,3,4,5,6,7] and k = 3
Output: [5,6,7,1,2,3,4]
Explanation:
rotate 1 steps to the right: [7,1,2,3,4,5,6]
rotate 2 steps to the right: [6,7,1,2,3,4,5]
rotate 3 steps to the right: [5,6,7,1,2,3,4]

Example 2:

Input: [-1,-100,3,99] and k = 2
Output: [3,99,-1,-100]
Explanation: 
rotate 1 steps to the right: [99,-1,-100,3]
rotate 2 steps to the right: [3,99,-1,-100]

Note:

  • Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
  • Could you do it in-place with O(1) extra space?
    class Solution {
        public void rotate(int[] nums, int k) 
    	{
            while(k>nums.length){k-=nums.length;}
    		int []temp=new int[k];
            for(int i=0;i<k;i++)
            {
                temp[i]=nums[nums.length-1-i];
            }
            for(int i=nums.length-1;i>=k;i--)
            {
            	nums[i]=nums[i-k];
            }
            for(int i=0;i<k;i++)
            {
            	nums[i]=temp[k-1-i];
            }
    	}
    }

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转载自blog.csdn.net/BJUT_bluecat/article/details/81155064
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