撸点代码,或难或易——3

//用户给定一个数a,决定有n个随机数相加得到这个数a
#include<iostream>
#include<windows.h>
#include<time.h>
using namespace std;
int main()
{
	int n;//用户输入的数
	int num;//用户决定由几个数相加
	int m = 0;
	cout << "请输入要得到的数字:";
	cin >> n;
	cout << "请输入有几个数合成:";
	cin >> num;
	srand((int)time(NULL));
	int *number;
	number = new int[num];
	for (int i = 0; i < num-1; i++)
	{
		number[i] = rand() % n / num + 1;
	}
	for (int i = 0; i < num - 1; i++)
	{
		m = m + number[i];
	}
	number[num - 1] = n - m;
	cout << n << "=";
	for (int i = 0; i < num-1; i++)
	{
		cout << number[i] << "+";
	}
	cout << number[num-1] << endl;
	system("pause");
}

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转载自blog.csdn.net/Do_or_die_hard/article/details/79048676
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