题目描述
本题要求计算A/B，其中A是不超过1000位的正整数，B是1位正整数。你需要输出商数Q和余数R，使得A = B * Q + R成立。
输入描述:
输入在1行中依次给出A和B，中间以1空格分隔。
输出描述:
在1行中依次输出Q和R，中间以1空格分隔。
输入例子:
123456789050987654321 7
输出例子:
17636684150141093474 3
我的代码：
import java.math.BigInteger;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner in=new Scanner(System.in);
BigInteger a=in.nextBigInteger();
BigInteger b=in.nextBigInteger();
in.close();
System.out.print(a.divide(b)+" ");
System.out.print(a.mod(b));
}
}
大佬的代码：
import java.util.Scanner;
/**
* Created by lang on 2016/1/18.
*/
public class Main {
int R = 0;
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
String A = sc.next();
int B = sc.nextInt();
bigDiv(A, B);
}
static void bigDiv(String A,int B){
StringBuffer Q = new StringBuffer();
char[] cA = A.toCharArray();
int r = 0;
int a = 0;
for (int i = 0; i < cA.length; i++) {
a = r * 10 + Integer.parseInt(String.valueOf(cA[i]));
Q.append(a/B);
r = a % B;
}
while (Q.charAt(0)=='0')Q.delete(0,1);
System.out.println(Q.toString()+" "+r);
}
}
另一位：
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
try {
String a = in.next();
int b = in.nextInt();
int s = 0;
for (int i = 0; i < a.length(); i++) {
int n = a.charAt(i) - '0';
s = s + n;
if (s >= b) {
System.out.print(s / b);
} else {
if (i != 0) {
System.out.print(0);
}
}
s = s % b * 10;
}
System.out.println(" " + s / 10);
} finally {
in.close();
}
}
}