c++11开多线程

#include "iostream"
#include "thread"
#include "string"
#include "functional"
#include "mutex"

using namespace std;

std::mutex glock;

class Th{
public:
    Th(){

    }
    
    void startThread(){
        typedef std::function<void(int,std::string)>  FN;
        FN fn = [=](int id,std::string name){
            volatile int count = 0;
            while( (count++) < 5){
                glock.lock();
                std::cout << "fn:  " << ", id=" << id << ", count=" << count  << ", name=" << name << std::endl;
                glock.unlock();

                this_thread::sleep_for(chrono::milliseconds(1000)); //延时1秒
            }
        };

        for (int id = 0; id < 3; id++){
            std::string name = "n" + std::to_string(id);
            std::thread t(fn,id,name);
            t.detach(); //几个线程同时启动，各跑各的
            //t.join();//每次只能有一个线程启动。等这个线程全部执行完，再启动执行下一个线程。实际不是多线程
        }
    }
private:
};


int main(void){

    Th th;
    th.startThread();

    glock.lock();
    std::cout << "main end" << std::endl;
    glock.unlock();

    while(1){
        
    }
    return 0;
}

执行结果：

$ ./a.exe
fn:  , id=0, count=1, name=n0
fn:  , id=1, count=1, name=n1
main end
fn:  , id=2, count=1, name=n2
fn:  , id=1, count=2, name=n1
fn:  , id=0, count=2, name=n0
fn:  , id=2, count=2, name=n2
fn:  , id=1, count=3, name=n1
fn:  , id=2, count=3, name=n2
fn:  , id=0, count=3, name=n0
fn:  , id=2, count=4, name=n2
fn:  , id=1, count=4, name=n1
fn:  , id=0, count=4, name=n0
fn:  , id=0, count=5, name=n0
fn:  , id=1, count=5, name=n1
fn:  , id=2, count=5, name=n2