Java实现单链表翻转实例代码

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Java实现单链表反转,递归和非递归两种形式。接下来通过本文给大家分享Java实现单链表翻转实例代码,需要的的朋友参考下

Java实现单链表反转,递归和非递归两种形式

/**

 * 反转单链表

 */

/** * 定义链表

 *

 * @author 16026

 *

 */

class Node {

  int val;

  Node next;

  public Node(int val) {

    this.val = val;

  }

}

public class ReverseList {

  /**

   * 反转链表

   *

   * @param head

   * @return

   */

  public static Node reverseList(Node head) {

    if (head == null || head.next == null) {

      return head;

    }

    Node reHead = null;// 定义新链表头结点

    while (head != null) {

      Node cur = head.next;// 记录下一个节点

      head.next = reHead;// 将rehead节点连接到head节点上

      reHead = head;// 让rehead指向head

      head = cur;// 将head指向下一个节点

    }

    return reHead;

  }

  /**

   * 递归反转链表

   *

   * @param head

   * @return

   */

  public static Node reverseList2(Node head) {

    if (head == null || head.next == null)

      return head;

    Node rehead = reverseList2(head.next);

    head.next.next = head;// 将头节点置于末端

    head.next = null;// 防止链表循环

    return rehead;

  }

  /**

   * 打印链表

   *

   * @param head

   */

  public static void printList(Node head) {

    if (head == null)

      return;

    while (head != null) {

      System.out.print(head.val + " ");

      head = head.next;

    }

  }

  /**

   * 测试

   *

   * @param args

   */

  public static void main(String[] args) {

    Node n1 = new Node(1);

    Node n2 = new Node(2);

    Node n3 = new Node(3);

    Node n4 = new Node(4);

    Node n5 = new Node(5);

    n1.next = n2;

    n2.next = n3;

    n3.next = n4;

    n4.next = n5;

    // Node rehead = reverseList(n1);

    Node rehead = reverseList2(n1);

    printList(rehead);

  }

}

运行结果如下: 

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转载自blog.csdn.net/u012602304/article/details/81809448
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