用一个数组实现两个栈(共享栈)

共享栈:

一个数组实现两个栈,第一个栈是开头,第二个栈是结尾:

用c语言实现,很简单,两个指针一个数组就够了,上代码:

#define _CRT_SECURE_NO_WARNINGS 1

#include <stdio.h>
#include <stdlib.h>
#include <assert.h>

#define N 100

typedef int shareStackDataType;

typedef struct shareStack{
	shareStackDataType data[N];//实现两个栈的数组
	int top1;
	int top2;
}shareStack;

void shareInit(shareStack* s)
{
	assert(s);//断言s指针
	s->top1 = -1;
	s->top2 = N;
	return;
}

void push1(shareStack* s, shareStackDataType value)
{
	assert(s);
	if (s->top1 >= s->top2)//判满
	{
		printf("栈满");
		return;
	}
	s->data[++s->top1] = value;
	return;
}

void push2(shareStack* s, shareStackDataType value)
{
	assert(s);
	if (s->top1 >= s->top2)
	{
		printf("栈满");
		return;
	}
	s->data[--s->top2] = value;
	return;
}

shareStackDataType pop1(shareStack* s)
{
	assert(s);
	if (shareEmpty1(s))//判空
	{
		printf("栈空");
		return 0;
	}
	return s->data[s->top1--];
}

shareStackDataType pop2(shareStack* s)
{
	assert(s);
	if (shareEmpty2(s))
	{
		printf("栈空");
		return 0;
	}
	return s->data[s->top2++];
}

int shareEmpty1(shareStack* s)
{
	return s->top1 == -1;
}

int shareEmpty2(shareStack* s)
{
	return s->top2 == N;
}

shareStackDataType peek1(shareStack* s)
{
	assert(s);
	if (shareEmpty1(s))
	{
		printf("栈空");
		return 0;
	}
	return s->data[s->top1];
}

shareStackDataType peek2(shareStack* s)
{
	assert(s);
	if (shareEmpty2(s))
	{
		printf("栈空");
		return 0;
	}
	return s->data[s->top2];
}

int main()
{
	shareStack s;
	shareInit(&s);
	push1(&s, 1);
	push1(&s, 2);
	push1(&s, 3);
	push1(&s, 4);
	push2(&s, 5);
	push2(&s, 6);

	printf("%d", pop1(&s));//4
	printf("%d", pop1(&s));//3
	printf("%d", pop2(&s));//6
	printf("%d", pop2(&s));//5
	printf("%d", pop1(&s));//2

	printf("%d", peek1(&s));//1

	system("pause");
	return 0;
}

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转载自blog.csdn.net/likunkun__/article/details/81809082