| 题目描述 |
People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.
Input
Each input file contains one test case which occupies a line containing the three decimal color values.
Output
For each test case you should output the Mars RGB value in the following format: first output “#”, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a “0” to the left.
Sample Input
15 43 71
Sample Output
#123456
| 解题思路 |
题目大意
进制转换．给定三个十进制数，将其转换为13进制数
思路
因为题目本身给的十进制数和要求转的13进制数都不超过两位,所以可以用数组代替写一个进制转换模块
| 代码设计 |
//AC代码
//zhicheng
#include<cstdio>
#include<iostream>
using namespace std;
//zhicheng
//August 10,2018
int main()
{
char c[14]={"0123456789ABC"};
printf("#");
for(int i=0;i<3;i++)
{
int rgb;
scanf("%d",&rgb);
printf("%c%c",c[rgb/13],c[rgb%13]);
}
printf("\n");
return 0;
}
有关PAT (Basic Level) 的更多内容可以关注 ——> PAT-B题解
有关PAT (Advanced Level) 的更多内容可以关注 ——> PAT-A题解