treap by:刘汝佳

备忘 白书代码的基础上有细微改进

// Rank Tree
// Rujia Liu
// 输入格式：
// m     操作有m个
// 1 x   插入元素x
// 2 x   删除元素x。如果成功，输入1，否则输出0
// 3 k   输出第k小元素。k=1为最小元素
// 4 x   输出值x的“名次”，即比x小的结点个数加1
#include<cstdlib>

struct Node {
  Node *ch[2]; // 左右子树
  int r; // 随机优先级
  int v; // 值
  int s; // 结点总数
  Node(int v = 0):v(v) { ch[0] = ch[1] = NULL; r = rand(); s = 1; }
  int cmp(int x) const {
    if (x == v) return -1;
    return x < v ? 0 : 1;
  }
  void maintain() {
    s = 1;
    if(ch[0] != NULL) s += ch[0]->s;
    if(ch[1] != NULL) s += ch[1]->s;
  }
};

void rotate(Node* &o, int d) {
  Node* k = o->ch[d^1]; o->ch[d^1] = k->ch[d]; k->ch[d] = o; 
  o->maintain(); k->maintain(); o = k;
}

void insert(Node* &o, int x) {
  if(o == NULL) o = new Node(x);
  else {
    int d = (x < o->v ? 0 : 1); // 不要用cmp函数，因为可能会有相同结点
    insert(o->ch[d], x);
    if(o->ch[d]->r > o->r) rotate(o, d^1);
  }
  o->maintain();
}

Node* find(Node* o, int x) {
  if(o == NULL) return NULL;
  if(x == o->v) return o;
  return x < o->v ? find(o->ch[0], x) : find(o->ch[1], x);
}

// 要确保结点存在
void remove(Node* &o, int x) {
  int d = o->cmp(x);
  int ret = 0;//没什么用的样子
  if(d == -1) {
    Node* u = o;
    if(o->ch[0] != NULL && o->ch[1] != NULL) {
      int d2 = (o->ch[0]->r > o->ch[1]->r ? 1 : 0);
      rotate(o, d2); remove(o->ch[d2], x);
    } else {
      if(o->ch[0] == NULL) o = o->ch[1]; else o = o->ch[0];
      delete u;//原版白书没有真实地将内存释放
    }
  } else
    remove(o->ch[d], x);
  if(o != NULL) o->maintain();
}

int kth(Node* o, int k) {
  if(o == NULL || k <= 0 || k > o->s) return 0;
  int s = (o->ch[0] == NULL ? 0 : o->ch[0]->s);
  if(k == s+1) return o->v;
  else if(k <= s) return kth(o->ch[0], k);
  else return kth(o->ch[1], k-s-1);
}

// 在以o为根的子树中，值比x小的结点总数加1
int rank(Node* o, int x) {
  if(o == NULL) return 1;
  if(x <= o->v) return rank(o->ch[0], x);
  return rank(o->ch[1], x) + (o->ch[0] == NULL ? 0 : o->ch[0]->s) + 1;
}

#include<cstdio>
const int INF = 0x7f7f7f7f;

int main() {
  int m, c, v;
  Node* root = new Node(INF);
  while(scanf("%d", &m) == 1) {
    while(m--) {
      scanf("%d%d", &c, &v);
      if(c == 1) insert(root, v);
      else if(c == 2) {
        Node* o = find(root, v);
        printf("%d\n", o == NULL ? 0 : 1);
        if(o != NULL) remove(root, v);
      }
      else if(c == 3) printf("%d\n", kth(root, v));
      else if(c == 4) printf("%d\n", rank(root, v));
    }
  }
  return 0;
}