F - AC me(15)
Ignatius is doing his homework now. The teacher gives him some articles and asks him to tell how many times each letter appears.
It's really easy, isn't it? So come on and AC ME.
Input
Each article consists of just one line, and all the letters are in lowercase. You just have to count the number of each letter, so do not pay attention to other characters. The length of article is at most 100000. Process to the end of file.
Note: the problem has multi-cases, and you may use "while(gets(buf)){...}" to process to the end of file.
Output
For each article, you have to tell how many times each letter appears. The output format is like "X:N".
Output a blank line after each test case. More details in sample output.
Sample Input
hello, this is my first acm contest!
work hard for hdu acm.Sample Output
a:1
b:0
c:2
d:0
e:2
f:1
g:0
h:2
i:3
j:0
k:0
l:2
m:2
n:1
o:2
p:0
q:0
r:1
s:4
t:4
u:0
v:0
w:0
x:0
y:1
z:0
a:2
b:0
c:1
d:2
e:0
f:1
g:0
h:2
i:0
j:0
k:1
l:0
m:1
n:0
o:2
p:0
q:0
r:3
s:0
t:0
u:1
v:0
w:1
x:0
y:0
z:0#include<stdio.h>
#include<string.h>
int main(void)
{
int len, i, book[10001] = {0}, c;
char str[100001];
while(gets(str))
{
len = strlen(str);
memset(book, 0, sizeof(book));
for(i = 0; i < len; i++)
{
if(str[i] >= 'a' && str[i] <= 'z')
{
book[str[i] - 'a']++;
}
}
for(c = 0; c < 26; c++)
{
printf("%c:%d\n", c + 'a', book[c]);
}
printf("\n");
}
return 0;
}
//以下为错误代码，注意为什么是错的
#include<stdio.h>
#include<string.h>
char str[100001], book[10001], c;
int main(void)
{
int len, i;
while(gets(str))
{
len = strlen(str);
memset(book, 0, sizeof(book));
for(i = 0; i < len; i++)
{
if(str[i] >= 'a' && str[i] <= 'z')
{
book[str[i]]++; //因为book数组虽然是个字符串，但是也应该是book【1】 = ‘a’，这种类型而不应该是book【a】 = 1， //这种类型
}
}
for(c = 'a'; c <= 'z'; c++)
{
printf("%c:%d\n", c, book[c]);
}
printf("\n");
}
return 0;
}