oracle INSTR字符串函数使用

<choose>
   <when test="newNo!=null and oldNo!=null">
      SHELVE_NO = CONCAT(#{newNo},substr(SHELVE_NO,INSTR(SHELVE_NO,'-',-1,1))+1)
      WHERE substr(SHELVE_NO,0,(INSTR(SHELVE_NO,'-',1,2)-1) = #{oldNo}
   </when>
</choose>

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转载自blog.csdn.net/qq_33888187/article/details/80476313