数据库题目

根据出生日期求年龄

表的结构

SET FOREIGN_KEY_CHECKS=0;

-- ----------------------------
-- Table structure for user
-- ----------------------------
DROP TABLE IF EXISTS `user`;
CREATE TABLE `user` (
  `uid` int(11) NOT NULL AUTO_INCREMENT,
  `birthday` datetime DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP,
  `uname` varchar(255) DEFAULT NULL,
  PRIMARY KEY (`uid`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of user
-- ----------------------------
INSERT INTO `user` VALUES ('1', '1995-08-05 22:57:49', '小波');

答案

SELECT uname 姓名,CASE WHEN
 DATE_ADD(birthday,INTERVAL YEAR(NOW())-YEAR(birthday) YEAR)>=NOW()
THEN YEAR(NOW())-YEAR(birthday)-1
ELSE
YEAR(NOW())-YEAR(birthday)
END 年龄
FROM user

　　注：本题我是采用MYSQL来作答。