题目描述:
Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.
Example:
Input:[1,2,3]
Output:3
Explanation:
Only three moves are needed (remember each move increments two elements):
[1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
给定n个数,每操作一步可以令n-1个数都加一,求需要多少步操作才能使得n个数都相等。令n-1数加一,也可以看做令一个数减一,那么先求数组中的最小值,再求其他数需要多少步才能等于它。
class Solution {
public:
int minMoves(vector<int>& nums) {
int min_num=INT_MAX;
for(int i=0;i<nums.size();i++)
min_num=min(min_num,nums[i]);
int result=0;
for(int i=0;i<nums.size();i++)
result+=nums[i]-min_num;
return result;
}
};