Problem L. Visual Cube
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 524288/524288 K (Java/Others)
Total Submission(s): 1473 Accepted Submission(s): 694
Problem Description
Little Q likes solving math problems very much. Unluckily, however, he does not have good spatial ability. Everytime he meets a 3D geometry problem, he will struggle to draw a picture.
Now he meets a 3D geometry problem again. This time, he doesn't want to struggle any more. As a result, he turns to you for help.
Given a cube with length a, width b and height c, please write a program to display the cube.
Input
The first line of the input contains an integer T(1≤T≤50), denoting the number of test cases.
In each test case, there are 3 integers a,b,c(1≤a,b,c≤20), denoting the size of the cube.
Output
For each test case, print several lines to display the cube. See the sample output for details.
这道题自己太菜，水题都写了好久。
#include<bits/stdc++.h>
using namespace std;
int main()
{
int t;
scanf("%d",&t);
int a,b,c;
while(t--)
{
scanf("%d%d%d",&a,&b,&c);
int point1=2*b;
int point2=0;
int chang=2*(a+b)+1;
int hh=2*b;
int logal=0;
for(int i=1;i<=hh;i++)
{
for(int j=1;j<=point1;j++)
{
cout<<'.';
}
for(int j=1+point1;j<=2*a +1+point1;j++)
{
if(i%2==0)
{
if(j%2==0)
{
cout<<'/';
}
else
cout<<'.';
}
else
{
if(j%2==0)
cout<<'-';
else
cout<<'+';
}
}
if(i>2*c+1)
logal=1;
if(i<=2*c+1)
{
for(int j=2*a +1+point1+1;j<=chang;j++)
{
if(i%2==1)
{
if(j%2==1)
{
cout<<'+';
}
else
cout<<'.';
}
else
{
if(j%2==1)
cout<<'|';
else
cout<<'/';
}
}
}
else
{
++point2;
///cout<<point2<<"&&&&&&&&&&&&&&&"<<endl;
for(int j=2*a +1+point1+1 ;j<=chang-point2;j++)
{
if(i%2==1)
{
if(j%2==1)
{
cout<<'+';
}
else
cout<<'.';
}
else
{
if(j%2==1)
cout<<'|';
else
cout<<'/';
}
}
for(int j=chang-point2+1;j<=chang;j++)
{
cout<<'.';
}
}
point1--;
cout<<endl;
}
for(int i=2*b+1;i<=2*b+2*c+1;i++)
{
for(int j=1;j<=2*a+1;j++)
{
if(i%2==1)
{
if(j%2==0)
cout<<'-';
else
cout<<'+';
}
else
{
if(j%2==0)
cout<<'.';
else
cout<<'|';
}
}
if(logal==0)
{
if(i>2*c+1)
{
++point2;
for(int j=2*a+2;j<=chang-point2;j++)
{
if(i%2==0)
{
if(j%2==0)
cout<<'/';
else
cout<<'|';
}
else
{
if(j%2==0)
cout<<'.';
else
cout<<'+';
}
}
for(int j=chang-point2+1;j<=chang;j++)
{
cout<<'.';
}
}
else
{
for(int j=2*a+2;j<=chang;j++)
{
if(i%2==0)
{
if(j%2==0)
cout<<'/';
else
cout<<'|';
}
else
{
if(j%2==0)
cout<<'.';
else
cout<<'+';
}
}
}
}
if(logal==1)
{
++point2;
for(int j=2*a+2;j<=chang-point2;j++)
{
if(i%2==0)
{
if(j%2==0)
cout<<'/';
else
cout<<'|';
}
else{
if(j%2==0)
cout<<'.';
else
cout<<'+';
}
}
for(int j=chang-point2+1;j<=chang;j++)
{
cout<<'.';
}
}
cout<<endl;
}
}
}