基于python中staticmethod和classmethod的区别

示例代码如下：

class A(object):

  def foo(self,x):

    print "executing foo(%s,%s)"%(self,x)

  @classmethod

  def class_foo(cls,x):

    print "executing class_foo(%s,%s)"%(cls,x)

  @staticmethod

  def static_foo(x):

    print "executing static_foo(%s)"%x 

a=A()

代码调用执行如下：

a.foo(1)

# executing foo(<__main__.A object at 0xb7dbef0c>,1)

-----------------------------------------------------------------

a.class_foo(1)

# executing class_foo(<class '__main__.A'>,1)

A.class_foo(1)

# executing class_foo(<class '__main__.A'>,1)

-----------------------------------------------------------------

a.static_foo(1)

# executing static_foo(1)

A.static_foo('hi')

# executing static_foo(hi

区别：

A、foo()的调用者必须是类A的一个实例，class_fool()与static_foo()的调用者既可以是类也可以是某个实例；

B、参数不同，foo()参数为self和其他参数，class_foo()参数使用类(cls)替换self，static_foo()则只有参数，没有self和类(cls)；

C、a.foo(1)中的foo()与a绑定，class_foo()是与类绑定的，而static_fool与这两者没有绑定；

class A(object):

  def foo(self):

    print "executing foo(%s,%s)"

  @classmethod

  def class_foo(cls,x):

    print "executing class_foo(%s,%s)"%(cls,x)

  @staticmethod

  def static_foo(x):

    print "executing static_foo(%s)"%x

a=A()

print a.foo()
print a.class_foo(1)
print a.static_foo(1)
print A.foo(a)
print A.static_foo(1)
print A.class_foo(1)