简单递归,忘记初始化折腾了半天,感觉英文题面也好难看懂啊。。
先确定第一棵树,将黑的数量统计并标记,第二棵数直接覆盖就好了,已经标记成黑色的就不计入。
/*
* @Author: Samson
* @Date: 2018-06-08 22:53:16
* @Last Modified by: Samson
* @Last Modified time: 2018-06-09 00:01:02
*/
// @URL : https://vjudge.net/problem/UVA-297
#include<bits/stdc++.h>
#include<algorithm>
#include <cstdlib>
#define INF 0x3f3f3f3f
using namespace std;
typedef long long LL;
const int MAXN = 1e5+10;
char s[1050];
int buf[33][33],ans;
void draw(char *s,int &p,int r,int c,int w)
{
char ch = s[p++];
if(ch == 'p')
{
draw(s,p,r,c+w/2,w/2);
draw(s,p,r,c,w/2);
draw(s,p,r+w/2,c,w/2);
draw(s,p,r+w/2,c+w/2,w/2);
}
else if(ch == 'f')
{
for(int i = r; i < r+w; ++i)
{
for(int j = c; j < c+w; ++j)
if(!buf[i][j])
{buf[i][j] = 1; ++ans;}
}
}
}
int main(void)
{
int T;
cin>>T;
while(T--)
{
memset(buf,0,sizeof buf);
int t = 2;
ans = 0;
while(t--)
{
scanf("%s",s);
int p = 0;
draw(s,p,1,1,32);
}
printf("There are %d black pixels.\n", ans);
}
return 0;
}