hdu 2222(AC自动机模板)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2222

思路:模板题

#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <cctype>
#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <queue>
#include <map>
#include <set>
#include <sstream>
#include<iomanip>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
const ll inff = 0x3f3f3f3f3f3f3f3f;
#define FOR(i,a,b) for(int i(a);i<=(b);++i)
#define FOL(i,a,b) for(int i(a);i>=(b);--i)
#define REW(a,b) memset(a,b,sizeof(a))
#define inf int(0x3f3f3f3f)
#define si(a) scanf("%d",&a)
#define sl(a) scanf("%I64d",&a)
#define sd(a) scanf("%lf",&a)
#define ss(a) scanf("%s",a)
#define mod int(1e9+7)
#define lc (d<<1)
#define rc (d<<1|1)
#define Pll pair<ll,ll>
#define P pair<int,int>
#define pi acos(-1)
const int N=550000;
int n;
string a;
struct AC_auto
{
    struct as{
    int val;
    int ne[26];
    void init()
    {
        val=0;
        REW(ne,0);
    }}ch[N];
    int f[N],last[N],sz;
    void clear(){ch[0].init();sz=1;}
    int idx(char a){return a-'a';}
    void add(string a)
    {
        int n=a.size(),p=0;
        FOR(i,0,n-1)
        {
            int c=idx(a[i]);
            if(ch[p].ne[c]==0)
            {
                ch[sz].init();
                ch[p].ne[c]=sz++;
            }
            p=ch[p].ne[c];
        }
        ch[p].val++;
    }
    void getfail()
    {
        queue<int> q;
        f[0]=0;
        int u=0;
        FOR(c,0,25)
        {
            u=ch[0].ne[c];
            if(u){f[u]=0;q.push(u);last[u]=0;}
        }
        while(q.size())
        {
            int r=q.front();q.pop();
            FOR(c,0,25)
            {
                int u=ch[r].ne[c];
                if(!u){ch[r].ne[c]=ch[f[r]].ne[c];continue;}
                q.push(u);
                int v=f[r];
                while(v&&!ch[v].ne[c])  v=f[v];
                f[u]=ch[v].ne[c];
                last[u]=ch[f[u]].val?f[u]:last[f[u]];
            }
        }
    }
    int fid(string a)
    {
        int u=0,cnt=0,n=a.size();
        FOR(i,0,n-1)
        {
            int c=idx(a[i]);
            u=ch[u].ne[c];
            int temp=0;
            if(ch[u].val)  temp=u;
            else if(last[u])  temp=last[u];
            while(temp)
            {
                cnt+=ch[temp].val;
                ch[temp].val=0;
                temp=last[temp];
            }
        }
        return cnt;
    }
}tr;
int main()
{
    cin.tie(0);
    cout.tie(0);
    int t;
    si(t);
    while(t--)
    {
        si(n);
        tr.clear();
        while(n--)
        {
            cin>>a;
            tr.add(a);
        }
        tr.getfail();
        cin>>a;
        int s=tr.fid(a);
        cout<<s<<endl;
    }
    return 0;
}

还有hdu2896也是道模板题,不过注意不只是小写字母只有26位,大概开到130左右

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2896

#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <cctype>
#include <iostream>
#include <algorithm>
#include <string>
#include <vector>
#include <queue>
#include <map>
#include <set>
#include <sstream>
#include<iomanip>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
const ll inff = 0x3f3f3f3f3f3f3f3f;
#define FOR(i,a,b) for(int i(a);i<=(b);++i)
#define FOL(i,a,b) for(int i(a);i>=(b);--i)
#define REW(a,b) memset(a,b,sizeof(a))
#define inf int(0x3f3f3f3f)
#define si(a) scanf("%d",&a)
#define sl(a) scanf("%I64d",&a)
#define sd(a) scanf("%lf",&a)
#define ss(a) scanf("%s",a)
#define mod int(1e9+7)
#define lc (d<<1)
#define rc (d<<1|1)
#define Pll pair<ll,ll>
#define P pair<int,int>
#define pi acos(-1)
const int N=100008;
int n,m,s[508],zz=1,szz=1;
char a[208],b[10008];
struct AC_auto
{
    struct as{
    int val;
    int ne[132];
    void init()
    {
        val=0;
        REW(ne,0);
    }}ch[N];
    int f[N],last[N],sz;
    void clear(){ch[0].init();sz=1;}
    int idx(char a){int zz=a;return zz;}
    void add(char *a,int x)
    {
        int n=strlen(a),p=0;
        FOR(i,0,n-1)
        {
            int c=idx(a[i]);
            if(ch[p].ne[c]==0)
            {
                ch[sz].init();
                ch[p].ne[c]=sz++;
            }
            p=ch[p].ne[c];
        }
        ch[p].val=x;
    }
    void getfail()
    {
        queue<int> q;
        f[0]=0;
        int u=0;
        FOR(c,0,130)
        {
            u=ch[0].ne[c];
            if(u){f[u]=0;q.push(u);last[u]=0;}
        }
        while(q.size())
        {
            int r=q.front();q.pop();
            FOR(c,0,130)
            {
                int u=ch[r].ne[c];
                if(!u){ch[r].ne[c]=ch[f[r]].ne[c];continue;}
                q.push(u);
                int v=f[r];
                while(v&&!ch[v].ne[c])  v=f[v];
                f[u]=ch[v].ne[c];
                last[u]=ch[f[u]].val?f[u]:last[f[u]];
            }
        }
    }
    void fid(char *a)
    {
        int u=0,n=strlen(a),sz=4,pp=7;
        FOR(i,0,n-1)
        {
            int c=idx(a[i]);
            u=ch[u].ne[c];
            int temp=0;
            if(ch[u].val)  temp=u;
            else if(last[u])  temp=last[u];
            while(temp)
            {
                s[zz++]=ch[temp].val;
                temp=last[temp];
                if(zz>=4)  break;
            }
        }
    }
}tr;
int main()
{
    cin.tie(0);
    cout.tie(0);
    si(n);
    tr.clear();
    FOR(i,1,n)
    {
        ss(a);
        tr.add(a,i);
    }
    tr.getfail();
    si(m);
    FOR(i,1,m)
    {
        ss(b);
        zz=1;
        tr.fid(b);
        if(zz==1)  continue;
        sort(s+1,s+zz);
        cout<<"web "<<i<<": ";
        FOR(j,1,zz-2)  cout<<s[j]<<" ";
        cout<<s[zz-1]<<endl;
        szz++;
    }
    cout<<"total: ";
    cout<<szz-1<<endl;
    return 0;
}

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转载自blog.csdn.net/qq_40858062/article/details/80474109