python 2018.7.6

1. dict
用大括号{} 括起来. 内部使用key:value的形式来保存数据
{'jay':'周杰伦', "jj":'林俊杰'}
注意:字典的key必须是可哈希的. 不可变的, value 没有限制
不是按照我们保存的顺序保存的, 无序的

2. 增删改查
1. dict[不存在的key] = value, setdefault()
2. pop(key). del dict[key]. popitem(), clear()
3. dict[存在的key] = 新值, d1.update(d2) 把d2的k-v更新到d1中
4. get(key, 默认值), setdefault(), dict[key]
# dic = {'jay':"周杰伦", "jj":"林俊杰", "eason":"陈奕迅"}
# print(dic)
# dic = {1: "马化腾", False:"阿里巴巴", "sylar":"帅的不行不行的", (1, "哈哈"): "元组", ["吼吼"]:"列表"}
# print(dic)

# 字典的相关操作
# 增加
# dic = {"昆凌":"周杰伦的老婆"}
# dic['国际章'] = "汪峰的老婆" # 新增
# dic['国际章'] = "雄壮的老外" # 如果key重复了. 会替换掉原来的value
#
# # dic.setdefault("马蓉", "王宝强的前任老婆")
# # dic.setdefault("马蓉", "宋哲的现任老婆????") # 如果字典中已经包含了这个key. 不再继续保存
# print(dic)


# dic = {"牌牌":"你去哪里了", "晓雪":"你快回来.", "雪雪": "又走了"}
# # ret = dic.pop("晓雪") # 删除一个元素. 返回这个元素的value值
# # print(ret)
# # del dic["雪雪"]
# ret = dic.popitem() # 返回给你的是一个元组.
#
# print(ret)
# # print(dic)

# dic = {"id":1, 'name':'李嘉诚', 'money':10000000}
# # 李嘉诚赔了500
# dic['money'] = dic['money'] - 500 # 用key去修改
# print(dic)

# dic1 = {"李晨":"范冰冰", "邓超":"孙俪", "王祖蓝":"李亚男"}
# dic2 = {"李晨":"张馨予", "郑凯":"baby", "王宝强":"马蓉"}
# dic1.update(dic2) # 把dic2中的内容更新到 dic1 , 如果存在了key. 替换. 如果不存在,添加
# print(dic1)
# print(dic2)

# dic = {"及时雨":"宋江", "小李广":"花荣", "黑旋风":"李逵", "易大师":"剑圣"}
# dic["大宝剑"] = "盖伦" # 新增
# dic["及时雨"] = "天老爷" # 修改
# print(dic["易大师是个脑残"]) # 查询, 如果key不存在,报错
# print(dic.get("易大师", "余小C")) # 如果key不存在. 返回None
# get()
# 可以通过key来获取value的值. 那么如果key不存在. 返回None.
# 可以给出一个默认值. 当key不存在的时候返回默认值

# dic = {"及时雨":"宋江", "易大师":"剑圣"}
# dic.setdefault("及时雨", "诺克萨斯") # 可以帮我们添加
# print(dic)
# ret = dic.setdefault("及时雨123", "hello")
# print(ret)
# print(dic)

# 1. 首先判断原来的字典中有没有这个key . 如果没有. 执行新增
# 2. 用这个key去字典中查询, 返回查到的结果
# dic = {"及时雨":"宋江", "易大师":"剑圣"}
# ret = dic.setdefault("及时雨", "西门庆")
# print(dic) #
# print(ret) #

3. 字典的常用方法
1. keys() 返回所有字典的key的集合(高仿列表)
2. values() 返回所有的value的集合
3. items() 返回键值对. 元组
dic = {"及时雨":"宋江", "易大师":"剑圣", "维恩":"暗影猎手"}
# print(dic.keys()) # 拿到所有的key, 返回key的集合. 像是列表. 但是不是列表
#
# for key in dic.keys(): # 可以进行迭代循环
# print(key)

# print(dic.values())
# for value in dic.values():
# print(value)
# dic = {"及时雨":"宋江", "易大师":"剑圣", "维恩":"暗影猎手"}
# print(dic.items()) # 拿到键值对
# # 遍历dict
# for k, v in dic.items():
# print(k , v)



# for k, v in dic.items():
# # = item # (key, value)
# # print(item) # (key, value)
# print(k,v)

解构:
a, b = (1, 2)
# a, b = (1, 2)
# print(a)
# print(b)

# a, b, c = ("马化腾", "马云", "马良")
# print(b)

# a, b = [1, 2]
# print(a, b)


4. 字典的嵌套
dic = {
"name":"汪峰",
"age": 58,
"wife":{
"name":"国际章",
"salary": 180000,
"age": 37
},
"children":[
{"name":"老大", "age": 18},
{"name":"老二", "age": 118}
]
}
print(dic["children"][1]["age"])

print(dic["wife"]['salary'])


5.字典for 循环
dic = {1: 'a', 2:'b', 3:'c'}
for a in dic: # 直接循环字典.拿到的是key

print(a)
print(dic[a])

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转载自www.cnblogs.com/xdlzs/p/9275600.html