XML是纯文本,你要判断它整个是否正确格式,相当于读入全部文件整个进行字符串分析更耗资源!
最简单的方法就是用异常判断。
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
private static boolean isXmlDocument(String rtnMsg){
boolean flag = true;try {
DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = documentBuilderFactory.newDocumentBuilder();
builder.parse( new InputSource( new StringReader( rtnMsg )));
} catch (Exception e) {
flag = false;
}
return flag;
}