原生JS实现图片拖拽移动与缩放

看一下最终效果,图片可以拖动,可以缩放

把代码贴出来,可以直接粘贴使用,大致的思想就是鼠标按下的时候获取当时的鼠标位置,要减去left和top值,移动的时候获取位置减去初始的值就得到移动的时候的left和top值

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8">
  <meta name="viewport" content="width=device-width, initial-scale=1.0">
  <meta http-equiv="X-UA-Compatible" content="ie=edge">
  <title>Document</title>
  <style>
      #box {
          width: 100px;
          height: 100px;
          background-color: aquamarine;
          position: absolute;
      }
      #father {
        width: 600px;
        height: 500px;
        background-color: rgb(226, 117, 184);
        position: relative;
      }
      img {
        width: 100%;
        height: 100%;
        cursor: move;
      }
      #scale { 
        width: 10px; 
        height: 10px; 
        overflow: hidden; 
        cursor: se-resize; 
        position: absolute; 
        right: 0; 
        bottom: 0; 
        background-color: rgb(122, 191, 238); 
      }
  </style>

</head>
<body>
    <div id="father">
      <div id="box">
        <img src="http://img4.imgtn.bdimg.com/it/u=4245161611,1195625695&fm=27&gp=0.jpg"/>
        <div id="scale"></div>
      </div>
    </div>
    <script type="text/javascript">
    // box是装图片的容器,fa是图片移动缩放的范围,scale是控制缩放的小图标
        var box = document.getElementById("box");
        var fa = document.getElementById('father');
        var scale = document.getElementById("scale");
        // 图片移动效果
        box.onmousedown=function(ev) {
            var oEvent = ev; 
            // 浏览器有一些图片的默认事件,这里要阻止
            oEvent.preventDefault();
            var disX = oEvent.clientX - box.offsetLeft;
            var disY = oEvent.clientY - box.offsetTop;
            fa.onmousemove=function (ev) {
                oEvent = ev;
                oEvent.preventDefault();
                var x = oEvent.clientX -disX;
                var y = oEvent.clientY -disY;

                // 图形移动的边界判断
                x = x <= 0 ? 0 : x;
                x = x >= fa.offsetWidth-box.offsetWidth ? fa.offsetWidth-box.offsetWidth : x;
                y = y <= 0 ? 0 : y;
                y = y >= fa.offsetHeight-box.offsetHeight ? fa.offsetHeight-box.offsetHeight : y;
                box.style.left = x + 'px';
                box.style.top = y + 'px';
            }
            // 图形移出父盒子取消移动事件,防止移动过快触发鼠标移出事件,导致鼠标弹起事件失效
            fa.onmouseleave = function () {
              fa.onmousemove=null;
              fa.onmouseup=null;
            }
            // 鼠标弹起后停止移动
            fa.onmouseup=function() {
               fa.onmousemove=null;
               fa.onmouseup=null;
            } 
        }
        // 图片缩放效果
        scale.onmousedown = function (e) {
          // 阻止冒泡,避免缩放时触发移动事件
          e.stopPropagation();
          e.preventDefault();
          var pos = {
            'w': box.offsetWidth,
            'h': box.offsetHeight,
            'x': e.clientX,
            'y': e.clientY
          };
          fa.onmousemove = function (ev) {
            ev.preventDefault();
            // 设置图片的最小缩放为30*30
            var w = Math.max(30, ev.clientX - pos.x + pos.w)
            var h = Math.max(30,ev.clientY - pos.y + pos.h)
            // console.log(w,h)

            // 设置图片的最大宽高
            w = w >= fa.offsetWidth-box.offsetLeft ? fa.offsetWidth-box.offsetLeft : w
            h = h >= fa.offsetHeight-box.offsetTop ? fa.offsetHeight-box.offsetTop : h
            box.style.width = w + 'px';
            box.style.height = h + 'px';
            // console.log(box.offsetWidth,box.offsetHeight)
          }
          fa.onmouseleave = function () {
            fa.onmousemove=null;
            fa.onmouseup=null;
          }
          fa.onmouseup=function() {
            fa.onmousemove=null;
            fa.onmouseup=null;
          } 
        }
        
    </script>
</body>
</html>

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转载自www.cnblogs.com/steamed-twisted-roll/p/9253077.html