C 求n的阶乘

1.题目

递归和非递归分别实现求n的阶乘

2.程序代码

#define _CRT_SECURE_NO_WARNINGS 1

#include <stdio.h>
#include <Windows.h>

int factorial1(int num)//非递归方式求n的阶乘
{
    int i = 0;
    int count = 1;

    for (i = 1; i <= num; i++)
    {
        count *= i;
    }
    return count;
}

int factorial2(int num)//递归方式求n的阶乘
{
    if (num == 1)
    {
        return 1;
    }
    return num * factorial2(num - 1);
}

int main()
{
    int num = 0;

    printf("please input a num:");
    scanf("%d", &num);

    printf("%d\n", factorial1(num));
    printf("%d\n", factorial2(num));

    system("pause");
    return 0;
}

3.执行结果

这里写图片描述

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转载自blog.csdn.net/k_a_irving/article/details/80096534