python 3.6.5 hashlib 和 hmac 模块

import hashlib

m=hashlib.md5()# m=hashlib.sha256()

m.update('hello'.encode('utf8'))
print(m.hexdigest()) #5d41402abc4b2a76b9719d911017c592

m.update('alvin'.encode('utf8'))

print(m.hexdigest()) #92a7e713c30abbb0319fa07da2a5c4af

m2=hashlib.md5()
m2.update('helloalvin'.encode('utf8'))
print(m2.hexdigest()) #92a7e713c30abbb0319fa07da2a5c4af

'''
注意:把一段很长的数据update多次,与一次update这段长数据,得到的结果一样
但是update多次为校验大文件提供了可能。
'''

import hashlib

# ######## 256 ########

hash = hashlib.sha256('898oaFs09f'.encode('utf8'))
hash.update('alvin'.encode('utf8'))
print (hash.hexdigest())#e79e68f070cdedcfe63eaf1a2e92c83b4cfb1b5c6bc452d214c1b7e77cdfd1c7

import hashlib
passwds=[
'alex3714',
'alex1313',
'alex94139413',
'alex123456',
'123456alex',
'a123lex',
]
def make_passwd_dic(passwds):
dic={}
for passwd in passwds:
m=hashlib.md5()
m.update(passwd.encode('utf-8'))
dic[passwd]=m.hexdigest()
return dic

def break_code(cryptograph,passwd_dic):
for k,v in passwd_dic.items():
if v == cryptograph:
print('密码是===>\033[46m%s\033[0m' %k)

cryptograph='aee949757a2e698417463d47acac93df'
break_code(cryptograph,make_passwd_dic(passwds))

模拟撞库破解密码

import hmac
h = hmac.new('暗号'.encode('utf8'))
h.update('hello'.encode('utf8'))
print (h.hexdigest())#320df9832eab4c038b6c1d7ed73a5940

#要想保证hmac最终结果一致,必须保证:
#1:hmac.new括号内指定的初始key一样
#2:无论update多少次,校验的内容累加到一起是一样的内容

import hmac

h1=hmac.new(b'egon')
h1.update(b'hello')
h1.update(b'world')
print(h1.hexdigest())

h2=hmac.new(b'egon')
h2.update(b'helloworld')
print(h2.hexdigest())

h3=hmac.new(b'egonhelloworld')
print(h3.hexdigest())

'''
f1bf38d054691688f89dcd34ac3c27f2
f1bf38d054691688f89dcd34ac3c27f2
bcca84edd9eeb86f30539922b28f3981
'''

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转载自www.cnblogs.com/yanxiatingyu/p/9243981.html