LinkedHashMap和HashMap的区别
LinkedHashMap是HashMap的子类,它和HashMap的区别是,可以按照节点插入的自然顺序(或者节点的操作顺序)来迭代所有节点。而且它的迭代比HashMap更快,因为HashMap遍历的数据结构要复杂一点,而LinkedHashMap用一个双链表来迭代。
HashMap的迭代器
HashMap的三种迭代器都是HashIterator的子类。
final class KeyIterator extends HashIterator
implements Iterator<K> {
public final K next() { return nextNode().key; }
}
final class ValueIterator extends HashIterator
implements Iterator<V> {
public final V next() { return nextNode().value; }
}
final class EntryIterator extends HashIterator
implements Iterator<Map.Entry<K,V>> {
public final Map.Entry<K,V> next() { return nextNode(); }
}
HashIterator抽象类
从源码可知,迭代器访问元素的顺序是从桶位数组第0位开始往后逐个桶位寻找,每个桶中的结构要么是单链表要么是实现了红黑树的双链表,都是链式结构,所以右可以逐个寻找。这也就是HashMap中元素的访问顺序,和hash&table.length
、hash值和Key值都有关系。
abstract class HashIterator {
Node<K,V> next; // next entry to return
Node<K,V> current; // current entry
int expectedModCount; // for fast-fail
int index; // current slot
HashIterator() {
expectedModCount = modCount;
Node<K,V>[] t = table;
current = next = null;
index = 0;
// 初始化next指向第一个节点
if (t != null && size > 0) { // advance to first entry
do {} while (index < t.length && (next = t[index++]) == null);
}
}
public final boolean hasNext() {
return next != null;
}
final Node<K,V> nextNode() {
Node<K,V>[] t;
Node<K,V> e = next;
if (modCount != expectedModCount)
throw new ConcurrentModificationException();
if (e == null)
throw new NoSuchElementException();
// 将next指向下一个节点
if ((next = (current = e).next) == null && (t = table) != null) {
do {} while (index < t.length && (next = t[index++]) == null);
}
return e;
}
public final void remove() {
Node<K,V> p = current;
if (p == null)
throw new IllegalStateException();
if (modCount != expectedModCount)
throw new ConcurrentModificationException();
current = null;
K key = p.key;
removeNode(hash(key), key, null, false, false);
expectedModCount = modCount;
}
}
LinkedHashMap的迭代器
LinkedHashMap是HashMap的子类,在HashMap的迭代器之上有添加了自己的迭代器,都是继承自LinkedHashIterator。
final class LinkedKeyIterator extends LinkedHashIterator
implements Iterator<K> {
public final K next() { return nextNode().getKey(); }
}
final class LinkedValueIterator extends LinkedHashIterator
implements Iterator<V> {
public final V next() { return nextNode().value; }
}
final class LinkedEntryIterator extends LinkedHashIterator
implements Iterator<Map.Entry<K,V>> {
public final Map.Entry<K,V> next() { return nextNode(); }
}
LinkedHashIterator抽象类的原理很简单,就是在双链表中依次访问。
abstract class LinkedHashIterator {
LinkedHashMap.Entry<K,V> next;
LinkedHashMap.Entry<K,V> current;
int expectedModCount;
LinkedHashIterator() {
next = head;
expectedModCount = modCount;
current = null;
}
public final boolean hasNext() {
return next != null;
}
final LinkedHashMap.Entry<K,V> nextNode() {
LinkedHashMap.Entry<K,V> e = next;
if (modCount != expectedModCount)
throw new ConcurrentModificationException();
if (e == null)
throw new NoSuchElementException();
current = e;
next = e.after;
return e;
}
public final void remove() {
Node<K,V> p = current;
if (p == null)
throw new IllegalStateException();
if (modCount != expectedModCount)
throw new ConcurrentModificationException();
current = null;
K key = p.key;
removeNode(hash(key), key, null, false, false);
expectedModCount = modCount;
}
}
LinkedHashMap.Entry
LinkedHashMap添加了一个内部类Entry来构建一个双链表,用于按照元素插入顺序迭代元素。
static class Entry<K,V> extends HashMap.Node<K,V> {
Entry<K,V> before, after;
Entry(int hash, K key, V value, Node<K,V> next) {
super(hash, key, value, next);
}
}
// 双链表头结点
transient LinkedHashMap.Entry<K,V> head;
// 双链表尾节点
transient LinkedHashMap.Entry<K,V> tail;
// 迭代器的访问顺序,true表示按访问顺序,false表示按照元素的插入顺序
// 在构造时指定,默认为false,指定后不能修改,决定了双链表的存储顺序
final boolean accessOrder;
看一个例子来展示accessOrder
的影响:
LinkedHashMap<String,Integer> map =
new LinkedHashMap<>(10, 0.75f, true);
map.put("gaoxiang1", 1);
map.put("gaoxiang3", 2);
map.put("gaoxiang4", 3);
map.put("gaoxiang2", 4);
map.put("gaoxiang0", 5);
map.put("gaoxiang", 6);
map.get("gaoxiang4");
map.get("gaoxiang1");
System.out.println(map);
//{gaoxiang3=2, gaoxiang2=4, gaoxiang0=5, gaoxiang=6, gaoxiang4=3, gaoxiang1=1}
保存插入顺序和访问顺序
那么双链表又是如何保存插入顺序的呢?
我们看看HashMap的源码,发现在putVal
方法结束前调用了afterNodeAccess
和afterNodeInsertion
方法,在removeNode
方法结束前调用了afterNodeRemoval
方法,在其他方法中也多次使用下面的三个方法,而这三个都是空方法。它们是为LinkedHashMap留下的。
// Callbacks to allow LinkedHashMap post-actions
void afterNodeAccess(Node<K,V> p) { }
void afterNodeInsertion(boolean evict) { }
void afterNodeRemoval(Node<K,V> p) { }
LinkedHashMap重写了这3个方法:
// 从双链表中删除e节点
void afterNodeRemoval(Node<K,V> e) {
LinkedHashMap.Entry<K,V> p =
(LinkedHashMap.Entry<K,V>)e, b = p.before, a = p.after;
p.before = p.after = null;
// 将e.before和e.after连接起来
if (b == null) // e是头结点时
head = a;
else
b.after = a;
if (a == null) // e是尾结点时
tail = b;
else
a.before = b;
}
// removeEldestEntry方法返回值总是false,所以该方法没有任何效果
void afterNodeInsertion(boolean evict) { // possibly remove eldest
LinkedHashMap.Entry<K,V> first;
if (evict && (first = head) != null && removeEldestEntry(first)) {
K key = first.key;
removeNode(hash(key), key, null, false, true);
}
}
// 记录节点的访问顺序
void afterNodeAccess(Node<K,V> e) {
LinkedHashMap.Entry<K,V> last;
// 如果accesOrder指定为true,访问节点后会将双链表中该节点移动到最后
if (accessOrder && (last = tail) != e) {
LinkedHashMap.Entry<K,V> p =
(LinkedHashMap.Entry<K,V>)e, b = p.before, a = p.after;
p.after = null;
if (b == null)
head = a;
else
b.after = a;
if (a != null)
a.before = b;
else
last = b;
if (last == null)
head = p;
else {
p.before = last;
last.after = p;
}
tail = p;
++modCount;
}
}
删除节点时,HashMap的removeNode
方法会调用afterNodeRemoval
,从双链表中删除该节点。
插入新节点时,HashMap的putVal
方法中会调用newNode
方法,而LinkedHashMap重写了newNode
方法,在双链表结尾添加该元素。
Node<K,V> newNode(int hash, K key, V value, Node<K,V> e) {
LinkedHashMap.Entry<K,V> p =
new LinkedHashMap.Entry<K,V>(hash, key, value, e);
linkNodeLast(p);
return p;
}
private void linkNodeLast(LinkedHashMap.Entry<K,V> p) {
LinkedHashMap.Entry<K,V> last = tail;
tail = p;
if (last == null)
head = p;
else {
p.before = last;
last.after = p;
}
}
而每次有效访问节点都会调用afterNodeAccess
方法,记录访问顺序。
public V get(Object key) {
Node<K,V> e;
if ((e = getNode(hash(key), key)) == null)
return null;
if (accessOrder)
afterNodeAccess(e);
return e.value;
}
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