Java模拟获取随机车牌号的两种方式

通过简单的几行代码，模拟用户选车牌的业务场景，这边只是简单的获取随机车牌，没有任何业务交互！这边提供了2种方式获取随机车牌，首先是定义好字母数组和车牌数组，方式一是每个字符都是随机获取字母或数字，方式二是把字母和数字都放在集合种，每次都打乱集合的顺序，获取集合的前5个元素。个人觉得方式一更好些！

有兴趣的可以做一个延伸，例如：显示过的再一次执行的时候就直接过滤掉等

以下是源码：

public class CarNumberController {
    
    

    private static Random random = new Random();
    private static final String[] arr1 = {
    
    "A","B","C","D","E","F","G","H","J","K","L","M","N","P","Q","R","S","T","U","V","W","X","Y","Z"};
    private static final String[] arr2 = {
    
    "0","1","2","3","4","5","6","7","8","9"};
    private static final boolean[] arr3 = {
    
    false,true};

    //获取随机字符（字母或数字）
    public static String getSingleStr(boolean flag){
    
    
        if (flag) {
    
    
            return arr1[random.nextInt(arr1.length)];
        } else {
    
    
            return arr2[random.nextInt(arr2.length)];
        }
    }

    //方式一
    public static String method1(){
    
    
        StringBuilder sb = new StringBuilder();
        sb.append("苏U");
        for (int j = 0; j < 5; j++) {
    
    
            sb.append(getSingleStr(arr3[random.nextInt(arr3.length)]));
        }
        return sb.toString();
    }

    //方式二
    public static String method2(){
    
    
        List<String> list = new ArrayList<>();
        list.addAll(Arrays.asList(arr1));
        list.addAll(Arrays.asList(arr2));
        Collections.shuffle(list);
        StringBuilder sb = new StringBuilder();
        sb.append("苏U");
        for (int i = 0; i < 5; i++) {
    
    
            sb.append(list.get(i));
        }
        return sb.toString();
    }

    public static void main(String[] args) {
    
    
        List<String> list = new ArrayList<>(50);
        for (int i = 0; i < 50; i++) {
    
    
            list.add(method1());
//            list.add(method2());
        }
        System.out.println(list);
    }
}

运行结果如下：