- 2000ms
- 65536K
While on summer camp, you are playing a game of hide-and-seek in the forest. You need to designate a “safe zone”, where, if the players manage to sneak there without being detected,they beat the seeker. It is therefore of utmost importance that this zone is well-chosen.
You point towards a tree as a suggestion, but your fellow hide-and-seekers are not satisfied. After all, the tree has branches stretching far and wide, and it will be difficult to determine whether a player has reached the safe zone. They want a very specific demarcation for the safe zone. So, you tell them to go and find some sticks, of which you will use three to mark anon-degenerate triangle (i.e. with strictly positive area) next to the tree which will count as the safe zone. After a while they return with a variety of sticks, but you are unsure whether you can actually form a triangle with the available sticks.
Can you write a program that determines whether you can make a triangle with exactly three of the collected sticks?
Input
The first line contains a single integer N , with 3 ≤ N ≤ 20 000, the number of sticks collected. Then follows one line with Npositive integers, each less than 260, the lengths of the sticks which your fellow campers have collected.
Output
Output a single line containing a single word: possible if you can make a non-degenerate triangle with three sticks of the provided lengths, and impossible if you can not.
样例输入1
3 1 1 1
样例输出1
possible
样例输入2
5 3 1 10 5 15
样例输出2
impossible
#include<iostream> #include<algorithm> using namespace std; int n; long long a[20001]; long long sum; int main() { while(scanf("%d",&n)!=EOF) { for(int i=0;i<n;i++) scanf("%lld",&a[i]); sort(a,a+n); bool flag=false; for(int i=0;i<n-2;i++) { sum=a[i]+a[i+1]; if(sum<=a[i+2]) continue; if(sum>a[i+2]) { flag=true; break; } } if(flag) printf("possible\n"); else printf("impossible\n"); } return 0; }