Python 列表中嵌套字典,key不同的情况下对value进行排序

列表中嵌套字典,key不同的情况下对value进行排序
可以将列表中的字典先放入到有一个字典中,对整个字典进行排序,在排序完成后,再转换成

from operator import itemgetter
def dict_list_sort(dict_list):
    dict_dict = {
    
    key:value for x in dict_list for key,value in x.items()}
    dict_list = sorted(dict_dict.items(), key=itemgetter(1))
    dict_sorted_list = [{
    
    x[0]:x[1]} for x in dict_list]
    return dict_sorted_list
view_list = [{
    
    '2023-05': 3}, {
    
    '2023-04': 23}, {
    
    '2023-03': 10}, {
    
    '2023-02': 3}, {
    
    '2023-01': 0}, {
    
    '2022-12': 0}, {
    
    '2022-11': 0}, {
    
    '2022-10': 0}, {
    
    '2022-09': 5}, {
    
    '2022-08': 5}, {
    
    '2022-07': 3}, {
    
    '2022-06': 27}]
view_list =dict_list_sort(view_list)
print('view_list:',view_list)

输出:
view_list: [{‘2023-01’: 0}, {‘2022-12’: 0}, {‘2022-11’: 0}, {‘2022-10’: 0}, {‘2023-05’: 3}, {‘2023-02’: 3}, {‘2022-07’: 3}, {‘2022-09’: 5}, {‘2022-08’: 5}, {‘2023-03’: 10}, {‘2023-04’: 23}, {‘2022-06’: 27}]

猜你喜欢

转载自blog.csdn.net/longe20111104/article/details/130710690
今日推荐