Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]
The total number of unique paths is 2.
这题的测试好恶心,居然左上角还有1的情况,请问机器人怎么站
public class Solution {
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
if(obstacleGrid==null || obstacleGrid.length==0) return 0;
int w = obstacleGrid.length, h = obstacleGrid[0].length;
int[][] dp = new int[w][h];
// dp[0][0] = 1;
if(obstacleGrid[0][0] ==1) return 0;
dp[0][0] = 1;
for(int i=1; i<w; i++){
if(obstacleGrid[i][0]==1){
dp[i][0] = 0;
}else{
dp[i][0] = dp[i-1][0];
}
}
for(int j=1; j<h; j++){
if(obstacleGrid[0][j]==1){
dp[0][j] = 0;
}else{
dp[0][j] = dp[0][j-1];
}
}
for(int i=1; i<w; i++){
for(int j = 1; j<h; j++){
if(obstacleGrid[i][j]==1){
dp[i][j]=0;
}else{
dp[i][j] = dp[i-1][j]+dp[i][j-1];
}
}
}
return dp[w-1][h-1];
}
}