指针与数组的关系

指针与数组的关系

#include<iostream>
using namespace std;

int main()
{
	
	//定义一个一维数组:
	int score[10]={1,2,3,4,5,6,7,8,9,10};
	
	//分配字节:
	cout<<sizeof(score)<<endl;
	
	//打印:
	cout<<"&score[0]="<<&score[0]<<" score="<<score<<endl;
	
	//引用数组的元素
	cout<<"score[0]="<<score[0]<<" *score="<<*score<<endl;
	cout<<"score[4]="<<score[4]<<" *(score+4)="<<*(score+4)<<endl;
	
	//定义指针变量:
	int* ps=score+5;
	//引用指针指向的内容
	cout<<"*ps="<<(ps)[0]<<endl;

	int a=1,b=2;
	int* pa=&a;
	int* pb=&b;
	
	/**pa=*pa+*pb;
	*pb=*pa-*pb;
	*pa=*pa-*pb;*/
	
	//pb=&a;
	//pa=&b;
	
	int temp=*pa;
	*pa=*pb;
	*pb=temp;
	
	cout<<*pa<<endl<<*pb<<endl;
	cout<<"a="<<a<<" b="<<b<<endl;
	
	int i=9;
	for(i=9;i<=10;i--)
	{
		cout<<"pc="<<score[i]<<endl;
		if(i==0)
		{
			break;
		}
	}
}

打印数组首个元素.

cout<<"&score[0]="<<&score[0]<<" score="<<score<<endl;

中间的a=2  b=1  有三个方法进行转换.

	int a=1,b=2;
	int* pa=&a;
	int* pb=&b;
	/**pa=*pa+*pb;
	*pb=*pa-*pb;
	*pa=*pa-*pb;*/
	//pb=&a;
	//pa=&b;
	int temp=*pa;
	*pa=*pb;
	*pb=temp;

最下面的就是倒叙输出数组.

int i=9;
	for(i=9;i<=10;i--)
	{
		cout<<"pc="<<score[i]<<endl;
		if(i==0)
		{
			break;
		}
	}
打印如下:


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转载自blog.csdn.net/superman___007/article/details/80637722
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