HCIP---重发布实验

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首先配置IP

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然后配置RIP和OSPF

[r1]ospf 1 router-id 1.1.1.1
[r1-ospf-1]a 0
[r1-ospf-1-area-0.0.0.0]network 192.168.12.1 0.0.0.0
[r1-ospf-1-area-0.0.0.0]network 192.168.13.1 0.0.0.0

[r2]ospf 1 router-id 2.2.2.2
[r2-ospf-1]a 0
[r2-ospf-1-area-0.0.0.0]network 192.168.12.2 0.0.0.0

[r3]ospf 1 router-id 3.3.3.3
[r3-ospf-1]a 0
[r3-ospf-1-area-0.0.0.0]network 192.168.13.3 0.0.0.0

[r2]rip 1
[r2-rip-1]v 2
[r2-rip-1]undo summary
[r2-rip-1]network 192.168.24.0

[r3]rip 1
[r3-rip-1]v 2
[r3-rip-1]undo summary
[r3-rip-1]network 192.168.34.0

[r4]rip 1
[r4-rip-1]v 2
[r4-rip-1]undo summary
[r4-rip-1]network 192.168.24.0
[r4-rip-1]network 192.168.34.0

然后对R1的回环重发布

[r1]ospf 1
[r1-ospf-1]import-route direct

再在R2,R3上配置双向重发布

[r2]ospf 1
[r2-ospf-1]import-route rip
[r2-ospf-1]q
[r2]rip 1
[r2-rip-1]import-route ospf

[r3]ospf 1
[r3-ospf-1]import-route rip
[r3-ospf-1]rip 1
[r3-rip-1]import-route ospf

这里查看R4的路由表发现1.1.1.1的路由被学习多次,原因是1.1.1.1以重发布的形式下发到ospf中后,R1的三个端口都会重发布,就导致R4从三个端口上都学习了1.1.1.1。解决方法是拒绝掉其他两个端口所下发的信息

[r4]ip ip-prefix dzy deny 192.168.12.0 24
[r4]ip ip-prefix dzy deny 192.168.13.0 24
[r4]int g0/0/0
[r4-GigabitEthernet0/0/0]rip metricin ip-prefix dzy 5
[r4-GigabitEthernet0/0/0]int g0/0/1
[r4-GigabitEthernet0/0/1]rip metricin ip-prefix dzy 5

最后用路由策略解决次优路径问题

[r2]ip ip-prefix dzy1 permit 192.168.12.0 24
[r2]route-policy dzy1 permit node 10
Info: New Sequence of this List.
[r2-route-policy]if-match ip-prefix dzy1
[r2-route-policy]apply cost-type type-1
[r2-route-policy]q
[r2]route-policy dzy1 permit node 20
Info: New Sequence of this List.
[r2-route-policy]q
[r2]ospf 1
[r2-ospf-1]import-route rip route-policy dzy1

[r3]ip ip-prefix dzy1 permit 192.168.13.0 24
[r3]route-policy dzy1 permit node 10
Info: New Sequence of this List.
[r3-route-policy]if-match ip-prefix dzy1
[r3-route-policy]apply cost-type type-1
[r3-route-policy]q
[r3]route-policy dzy1 permit node 20
Info: New Sequence of this List.
[r3-route-policy]q
[r3]ospf 1
[r3-ospf-1]import-route rip route-policy dzy1

[r2]ip ip-prefix dzy2 permit 192.168.34.0 24
[r2]int g0/0/0
[r2-GigabitEthernet0/0/0]rip metricout ip-prefix dzy2 2

[r3]ip ip-prefix dzy2 permit 192.168.24.0 24
[r3]int g0/0/0
[r3-GigabitEthernet0/0/0]rip metricout ip-prefix dzy2 2

配完之后R1和R4的负载均衡消失,次优路径也就解决

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转载自blog.csdn.net/weixin_54986292/article/details/129895873
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