题目描述:
1、对输入的字符串进行加解密,并输出。
2加密方法为:
当内容是英文字母时则用该英文字母的后一个字母替换,同时字母变换大小写,如字母a时则替换为B;字母Z时则替换为a;
当内容是数字时则把该数字加1,如0替换1,1替换2,9替换0;
其他字符不做变化。
3、解密方法为加密的逆过程。
Java实现:
import java.util.*; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); while(sc.hasNext()) { String password = sc.nextLine(); String result = sc.nextLine(); encrypt(password.toCharArray()); unEncrypt(result.toCharArray()); } } private static void encrypt(char[] password) { for (int i = 0; i < password.length; i++) { if(Character.isLowerCase(password[i])) { if (password[i] == 'z') password[i] = 'A'; else password[i] = (char)(password[i] - 31); } else if (Character.isUpperCase(password[i])) { if (password[i] == 'Z') password[i] = 'a'; else password[i] = (char)(password[i] + 33); } else if (Character.isDigit(password[i])) { if (password[i] == '9') password[i] = '0'; else password[i] = (char)(password[i] + 1); } } System.out.println(String.valueOf(password)); } private static void unEncrypt(char[] result) { for (int i = 0; i < result.length; i++) { if(Character.isLowerCase(result[i])) { if (result[i] == 'a') result[i] = 'Z'; else result[i] = (char)(result[i] - 33); } else if (Character.isUpperCase(result[i])) { if (result[i] == 'A') result[i] = 'z'; else result[i] = (char)(result[i] + 31); } else if (Character.isDigit(result[i])) { if (result[i] == '0') result[i] = '9'; else result[i] = (char)(result[i] - 1); } } System.out.println(String.valueOf(result)); } }
知识点:
- A~Z:65~90
- a~z:97~122
- 0~9:48~57