c++拷贝构造函数中的指针拷贝错误

 先定义一个Human

 class Human {
public:  
	Human(); 
	Human(int age, int salary);
	Human(const Human& man);
	void setaddr(const char* addr);
	const char *getAddr()const;

private:
	string name = "Unknown";
	int age = 28;
	int salary;  
	char* addr = NULL;

}; 

实现一下他的成员函数

const char * Human::getAddr ()const {
	return addr;
}

Human::Human() { 
	name = "无名氏";
	age = 18;
	salary = 30000;
	strcpy_s(addr, ADDR_LEN, "China");
}



Human::Human(const Human& man) {
	salary = man.salary;
	age = man.age;
	name = man.name;
	addr = man.addr;

}

void Human::setaddr(const char* addr) {
	if (!addr) {
		return;
	}

	 strcpy_s(this->addr, ADDR_LEN,addr);  

}



Human::Human(int age, int salary)
{
	this->age = age;
	this->salary = salary; 
	this->name = "无名";
	strcpy((char*)addr,  "China");
}

Main函数

int main(void) {

	Human h1;
	Human h2(h1);
	 
	cout << "H1:" << h1.getAddr() << endl;

	cout << "H2:" << h2.getAddr() << endl;

	cout << "h1更改addr后" << endl;
 
 
	h1.setaddr("Franch");
	cout << "H1:" << h1.getAddr() << endl;

	cout << "H2:" << h2.getAddr() << endl;
	return 0;
}

Main函数

int main(void) {

	Human h1;
	Human h2(h1);
	 
	cout << "H1:" << h1.getAddr() << endl;

	cout << "H2:" << h2.getAddr() << endl;

	cout << "h1更改addr后" << endl;
 
 
	h1.setaddr("Franch");
	cout << "H1:" << h1.getAddr() << endl;

	cout << "H2:" << h2.getAddr() << endl;
	return 0;
}

执行结果

 出现问题: 明明只更改了h1的addr，但是h2的addr也随着更改，也变成了Franch

这是因为在调用了拷贝构造函数后，h1 h2 的addr 指向同一块内存，h1的addr更改了这一块内存，而h2的addr也是这段内存，所以h1 h2 的addr都随之更改。

解决方案如下：

只需要给addr开辟一个新的内存即可

void Human::setaddr(const char* addr) {
	if (!addr) {
		return;
	}

   this->addr = new char[ADDR_LEN];
	 strcpy_s(this->addr, ADDR_LEN,addr);  
 

}

Human::Human() { 
	name = "无名氏";
	age = 18;
	salary = 30000;
	 
	 addr = new char[ADDR_LEN];
	strcpy_s(addr, ADDR_LEN, "China");
}

 问题解决