链表交换排序

# include<stdio.h>
# include<stdlib.h>

struct ListNode {
    int data;
    struct ListNode *next;
};

void printlist( struct ListNode *L )
{
     struct ListNode *p = L;
     while (p) {
           printf("%d ", p->data);
           p = p->next;
     }
     printf("\n");
}
struct ListNode *readlist(){
	struct ListNode *L ;
	struct ListNode *p;
	int i = 1;
	int n;
	scanf("%d",&n);
	while(n!=-1){
		struct ListNode *s  = (struct ListNode *)malloc(sizeof(struct ListNode));
		s->next = NULL;
		s->data = n;
		
		if(i == 1){
			L = s;
			p = s;
		}
		else{
			p->next = s;
			p = s;
		}
		i++;
		scanf("%d",&n);	
	}
	return L;
}

void Sort(struct ListNode **L){
	int count = 0;
	struct ListNode *p = *L;
	while(p!=NULL){
		count++;
		p=p->next;
	} // 5 4 3 2 1 
	printf("count:%d\n",count);
	for(int i = 0;i<count-1;i++){  //控制多少次 
		struct ListNode *p = *L;
		struct ListNode *q = p->next;
		int m = count-i-1;  //****** 交换操作到那一位置 
		while(m--){               //
			if(p->data < q->data){
				int temp = p->data;
				p->data = q->data;
				q->data = temp;
			}
			p = q;
			q = q->next;
		}
	}
	
}
 
int main()
{
    struct ListNode *L;
    L = readlist();
    Sort(&L);
    printlist(L);
    return 0;
}

思路和数组冒泡一样。

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转载自blog.csdn.net/qq_42018521/article/details/123610746